Help me please! i’m very behind.
1 answer:
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Answer:
On a coordinate plane, the x-axis is labeled Perimeter of a square, and the y-axis is labeled Side length of a square. A line goes through points (4, 1), (8, 2).
Step-by-step explanation:
Let
x ----> the perimeter of the square
y ---> the side length of the square
Remember that
The perimeter of the square is given by the expression
where
b is the length side of the square
solve for b
That means
A ordered pair in the coordinate plane following the rule
(x,y) -----> (x,x/4)
The y-coordinate is equal to the x-coordinate divided by 4
y=x/4
therefore
On a coordinate plane, the x-axis is labeled Perimeter of a square, and the y-axis is labeled Side length of a square. A line goes through points (4, 1), (8, 2).
Because
For the point (4,1)
substitute in the linear equation the value of x
y=4/4=1 ----> is ok
For the point (8,2)
substitute in the linear equation the value of x
y=8/4=2 ----> is ok
Answer:
a. 15h + 40 ≤ 140
b. h ≤ 6.6
<em>Note: The question is missing a table. The table is shown in the attachment below.</em>
Step-by-step explanation:
a. The school group has $140 to spend, and so can only spend an amount less than or equal to $140 when renting the main hall.
The cost of renting the main includes an hourly rate of $15 and a set-up fee of $40.
Let h represent the number of hours the group can rent the hall.
Cost of renting the main hall, C is given by:
15h + 40 ≤ 140
b. Solution of the inequality:
15h + 40 ≤ 140
15h ≤ 140 - 40
15h ≤ 100
h ≤ 100/15
h ≤ 6.6
Therefore, the main hall can only be rented for a maximum of 6.6 hours or less
