Answer:
Therefore there are 35 number of 2-point questions and 15 number of 5-point questions.
Step-by-step explanation:
i) let the number of 2 point question is x.
ii) let the number of 5 point questions be y
iii) total number of questions is 50
iv) therefore x + y = 50
v) it is also given that 2x + 5y = 145
vi) solving for the two equations found in iv) and v). Multiplying iv) by 2 we get
2x + 2y = 100
vii) subtracting equation vi) from equation v) we get 3y = 45.
viii) Therefore y = 15.
ix) using the value in viii) and substituting in iv) we get x + 15 = 50.
Therefore x = 50 - 15 = 35
x) Therefore there are 35 number of 2-point questions and 15 number of 5-point questions.
Answer:
SAS Postulate
Step-by-step explanation:
You can use the SAS (side, angle, side) postulate that says "if two sides and the included angle of one triangle are congruent to two sides and the included angle of another triangle, then the triangles are congruent"
Side AB is proportionate to DE and
Side AC is proportionate to DF.
Angle A and Angle D are the same; and is between the two sides
I hope this helps.
Hi there,
the first part equals 4/45 and the second part equals 7/9
4/45 divided by 7/9 = 0.00141093474
Hope this helps :)<span>
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Mary = (1/3)x
Erin = x - 8
John = x
Here is your equation:
(1/3)x + (x - 8) + x = 267
Take it from here.
Answer:
a. V = (20-x) 
b . 1185.185
Step-by-step explanation:
Given that:
- The height: 20 - x (in )
- Let x be the length of a side of the base of the box (x>0)
a. Write a polynomial function in factored form modeling the volume V of the box.
As we know that, this is a rectangular box has a square base so the Volume of it is:
V = h *
<=> V = (20-x)
b. What is the maximum possible volume of the box?
To maximum the volume of it, we need to use first derivative of the volume.
<=> dV / Dx = -3 + 40x
Let dV / Dx = 0, we have:
-3 + 40x = 0
<=> x = 40/3
=>the height h = 20/3
So the maximum possible volume of the box is:
V = 20/3 * 40/3 *40/3
= 1185.185
