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3 years ago

9x-4 (x-3)+72 Find X A. 6 B. 12 C. 17 D. 19

Mathematics

1 answer:

Jet001 [13]3 years ago

3 0

Answer:

Step-by-step explanation:

9x-4 (x-3)+72

9x-4x+12+72

5x+84

5x/5 + 84/5

x=17

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What's the answer to this questions?

tia_tia [17]

I believe the answer is 2 :) .

6 0

3 years ago

The length of a rectangle is 4 centimeters more than twice its width of the perimeter of the rectangle is 86centimeters find the

lana66690 [7]

Answer:

$Width= 13 cm$

$length=30cm$

Step-by-step explanation:

Let the length of the rectangle be 'L'

And the width of the rectangle be 'W'

$Perimeter= 86 cm$

According to the statement:

$Length= 2*Width+4\\L=2W+4$

Perimeter of a rectangle= 2(Length+Width)

$86=2(2W+4+W)\\86/2=3W+4\\43=3W+4\\3W=43-4\\3W=39\\W=39/3\\W=13 cm\\\\Length(L)=2W+4\\=2(13)+4=26+4=30 cm\\Length=30 cm$

$Width= 13 cm$

$length=30cm$

6 0

3 years ago

ALOT OF POINTS IF YOU HELP ME PLEASE EXPLAIN

Svetllana [295]

Answer:

Helena gave the answer as (7y²z + 6yz²- 5 - 3yz² + 2) which is equivalent to (7y²z + 3yz² - 3).

Step-by-step explanation:

Misha's group was asked to write an expression equivalent to

7y²z + 3yz² - 3

When Mr. Chen checked their answers, he found only one to be correct.

And she was Helena.

Helena gave the answer as (7y²z + 6yz²- 5 - 3yz² + 2) which is equivalent to (7y²z + 3yz² - 3).

Because, (7y²z + 6yz²- 5 - 3yz² + 2)

= 7y²z + (6yz² - 3yz²) - (5 - 2)

= 7y²z + 3yz² - 3 (Answer)

4 0

3 years ago

Write a polynomial function in standard form with zeros at 0, 1, and 2.

BARSIC [14]

Answer:

Step-by-step explanation:

f(x)=(x-0)(x-1)(x-2)

=x(x^2-3x+2)

or f(x)=x^3-3x^2+2x

3 0

3 years ago

Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre

Len [333]

Answer:

In the operation, simplify

9-a² = (3-a)(3+a)

Factorize

4a²-4a-24-------------------divide each term by 4

a²-a-6-------------------------factorize

a²-3a+2a-6

a(a-3)+2(a-3)

(a+2)(a-3)

Factorize

a²-6a+9

a²-3a-3a+9

a(a-3)-3(a-3)

(a-3)(a-3)

Rewrite operation as

$\frac{8}{(3-a)(3+a)} /\frac{(a+2)(a-3)}{(a-3)(a-3)}$

Multiply by the recipricol

$\frac{8}{(3-a)(3+a)} *\frac{(a-3)(a-3)}{(a+2)(a-3)}$

cancel the similar terms

$\frac{8}{(3-a)(3+a)} *\frac{(a-3)}{(a+2)}$

6 0

3 years ago