Answer:
6.98%
Explanation:
% error= |experimental value - actual value|/actual value × 100
Experimental value= 4.6 cm
Actual value= 4.3 cm
% error = |4.6-4.3|/4.3 × 100
% error = 6.98%
Bonds formed between atoms can be classified as ionic and covalent
Ionic bonds are formed between atoms that have a high difference in the electronegativity values.
In contrast, bonds formed between atoms that have a difference in electronegativity lower than the ionic counterparts are polar covalent bonds. If the atoms have very similar electronegativities, they form non-polar covalent bonds.
In H2S, the S atom is bonded to 2 H atoms. The electronegativity of H = 2.2 and S= 2.56. Since the difference is not high the bond formed will be covalent (polar covalent).
Answer:
We need 7.94 grams of Ca3(PO4)2
Explanation:
Step 1: Data given
Volume of Ca3(PO4)2 = 200 mL = 0.2 L
Molarity = 0.128 M
Molar mass of Ca3(PO4)2 = 310.18 g/mol
Step 2: Calculate moles of Ca3(PO4)2
Moles = molarity * volume
Moles Ca3(PO4)2 = 0.128 M * 0.2 L
Moles Ca3(PO4)2 = 0.0256 moles
Step 3: Calculate mass of Ca3(PO4)2
Mass Ca3(PO4)2 = moles Ca3(PO4)2 * molar massCa3(PO4)2
Mass Ca3(PO4)2 = 0.0256 moles * 310.18 g/mol
Mass Ca3(PO4)2 = 7.94 grams
We need 7.94 grams of Ca3(PO4)2
Answer:
P₂= 116.7 atm
Explanation:
Here apply the Boyle's law equations that states :at constant temperature the volume of a dry mass of a gas is inversely proportional to its pressure.
This is simplified as;
P₁V₁=P₂V₂ where P is pressure and V is volume
Given that;
P₁=1
V₁=1.81 m³
P₂=?
V₂=1.55*10^-2 m³
Apply the formula
1*1.81 =P₂*1.55*10^-2 m³
1.81/1.55*10^-2 =P₂
P₂= 116.7 atm
