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vekshin1
3 years ago
5

Cutting a piece of paper in half proves that solids have no definite shape. True or False?

Chemistry
1 answer:
erma4kov [3.2K]3 years ago
8 0
False. Solids have a definite shape and volume. Cutting a paper (solid) in half will alter the shape of the original solid and give it a new shape and volume instead. A solid will always have a definite shape. If not, it's not a solid.
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Homeostasis means maintaining
Zielflug [23.3K]

Answer:

Homeostasis is the tendency to resist change in order to maintain a stable, relatively constant internal environment. Homeostasis typically involves negative feedback loops that counteract changes of various properties from their target values, known as set points.

Explanation:

So D. Glad to help! :D

4 0
3 years ago
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La densidad del óxido de magnesio. MgO, es de 3.581 g/cm3 El MgO, es de 3.581 g/cm3 El MgO cristaliza con ordenamiento cúbico co
Jobisdone [24]

Answer:

a=4.213cm

r=1.490x10^{-8}cm

Explanation:

Hola.

En este caso, para calcular la longitud (a) de una cara de celda unitaria, consideramos la siguiente ecuación:

\rho =\frac{#at*M}{a^3N_A}

En la que consideramos el número de átomos por celda (4 para FCC), la masa molar (40.3 g/mol para MgO) y el número de avogadro para obtener:

3.581g/mol = \frac{4atom/celda*40.3g/mol}{a^3*6.02x10^{23}atom/mol}

Despejando para a, obtenemos:

a^3 = \frac{4atom/celda*40.3g/mol}{3.581g/cm^3*6.02x10^{23}atom/mol}\\\\a=\sqrt[3]{7.478cm^3} \\\\a=4.213cm

Finalmente, el radio lo calculamos como:

r=\frac{\sqrt{2}*a}{4}=\frac{\sqrt{2}*4.213x10^{-8}cm}{4}\\\\r=1.490x10^{-8}cm

¡Saludos!

6 0
3 years ago
What is the symbol for copper
bekas [8.4K]
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7 0
3 years ago
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r-ruslan [8.4K]
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6 0
3 years ago
If an atom of Oxygen (8 protons, 8 neutrons, and 8 electrons) gains two electrons, what is the charge of the ion formed?
Alexxx [7]

Answer:

It becomes negative

Explanation:

protons carry a positive charge

neutrons carry a neutral charge

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if we add 2 more electrons, the charge of the ion becomes negative

thank you.

4 0
3 years ago
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