Determine the empirical formula of a compound containing 47.37 grams of carbon, 10.59 grams of hydrogen, and 42.04 grams of oxyg
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Answer:
The answer is "29.081"
Explanation:
when the empty 2.00 L container of 1000 kg, a sample of HI (9.30 x 10-3 mol) has also been placed.
Its density of I 2 was 6.29x10-4 M if the balance had been obtained, then we have to get the intensity of equilibrium then:
It is defined that:
Now, we calculate the position:
For the reaction , you can calculate the value of Kc at 1000 K.
data expression for Kc
calculating the reverse reaction
Considering the definition of mole fraction, the mole fraction of O₂ in the mixture is 0.434.
<h3>Definition of mole fraction</h3>The molar fraction is a way of measuring the concentration that expresses the proportion in which a substance is found with respect to the total moles of the solution.
In other words, the mole fraction expresses the concentration of solute in a solution as the ratio of moles of substance to total moles of solution:
In this case, you know a gas mixture used for anesthesia contains 4.60 mol oxygen (O₂) and 6.00 mol nitrous oxide (N₂O).
So, the total moles of the solution can be calculated as:
Total moles = moles of oxygen (O₂) + moles of nitrous oxide (N₂O)
Then:
Total moles= 4.60 moles + 6 moles
Total moles= 10.60 moles
Finally, the more fraction of O₂ can be calculated as follow:
Solving:
<u><em>Mole fraction O₂ = 0.434</em></u>
Finally, the mole fraction of O₂ in the mixture is 0.434.
Learn more about mole fraction:
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