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3 years ago

Show the calculation of the mass of Ca3(PO4)2 needed to make 200 ml of a 0.128 M solution.

Chemistry

1 answer:

gavmur [86]3 years ago

3 0

Answer:

We need 7.94 grams of Ca3(PO4)2

Explanation:

Step 1: Data given

Volume of Ca3(PO4)2 = 200 mL = 0.2 L

Molarity = 0.128 M

Molar mass of Ca3(PO4)2 = 310.18 g/mol

Step 2: Calculate moles of Ca3(PO4)2

Moles = molarity * volume

Moles Ca3(PO4)2 = 0.128 M * 0.2 L

Moles Ca3(PO4)2 = 0.0256 moles

Step 3: Calculate mass of Ca3(PO4)2

Mass Ca3(PO4)2 = moles Ca3(PO4)2 * molar massCa3(PO4)2

Mass Ca3(PO4)2 = 0.0256 moles * 310.18 g/mol

Mass Ca3(PO4)2 = 7.94 grams

We need 7.94 grams of Ca3(PO4)2

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2 years ago

When 74.8g of alanine C3H7NO2 are dissolved in 1450.g of a certain mystery liquid X, the freezing point of the solution is 8.30°

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Answer: The mass of potassium bromide that must be dissolved in the same mass of X to produce the same depression in freezing point is 58.2 grams

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Depression in freezing point is given by:

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i= vant hoff factor = 1 (for non electrolyte)

$K_f$ = freezing point constant =

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$K_f=14.3^0C/m$

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$x=58.2g$

Thus the mass of potassium bromide that must be dissolved in the same mass of X to produce the same depression in freezing point is 58.2 grams

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3 years ago