Answer:
We have;
7 pencil boxes and 5 eraser boxes
Step-by-step explanation:
To find the smallest number of boxes that can be bought, what we simply do is to find the lowest common multiple of the content of each of the boxes
hence, we are going to find the lowest common multiple of 10 and 14
The lowest common multiple of 10 and 14 is 70
So the smallest number of pencil boxes that can be bought is 70/10 = 7
The smallest number of eraser boxes would be 70/14 = 5
Answer:
hope this helps
Step-by-step explanation:
part.1
Answer:
To solve this inequality you need to get m by itself
3m+10<30 (First subtract 10 from each side)
3m<20 (10-10=0, 30-10=20) (Then divide each side by 3)
m< 20/3 or 6.666666
So your answer is any that is less than 6.66666
Your answer would be 5
5
Hope this helps ;)
Answer:
Step-by-step explanation:
Simplifying 4y + -70 = 12y + 2
Add -12y to each side of the equation. -70 + 4y + -12y = 2 + 12y + -12y
Add 70 to each side of the equation. -70 + 70 + -8y = 2 + 70
Divide each side by -8.
So y = -9 is your answer.
Hope I Helped!!!
