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Lesechka [4]
3 years ago
8

Triangle ABC is translated 1 unit right and 2 units down. What are the coordinates of the translated triangle?

Mathematics
2 answers:
Alona [7]3 years ago
8 0
A' = (2,1)
B' = (5,3)
C' = (4,-1)
Pavlova-9 [17]3 years ago
3 0

Answer:

A'(2,1)

B'(5,3)

C'(4,-1)

Step-by-step explanation:

We have been given an image of a triangle ABC, which is translated 1 unit right and 2 units down. We are asked to find the coordinates of the translated triangle.

We know that translation to right by 'a' units means adding 'a' units to x-coordinate and translation by 'a' units down means subtracting 'a' units from y-coordinates.

So after applying the given translation coordinates of translated triangle will be:

A(1,3)\rightarrow A'(1+1,3-2)=A'(2,1)

B(4,5)\rightarrow B'(4+1,5-2)=B'(5,3)

C(3,1)\rightarrow C'(3+1,1-2)=C'(4,-1)

Therefore, the coordinates of the translated triangle are:

A'(2,1)

B'(5,3)

C'(4,-1)

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The polygons are similar. The area of one polygon is given. Find the area of the other polygon.
kap26 [50]

Answer:

90 cm²

Step-by-step explanation:

Given that both triangles are similar, it follows that the ratio of their area equals the square of their corresponding sides.

Let the area of the other triangle be x. Therefore:

\frac{10}{x} = \frac{4^2}{12^2}

\frac{10}{x} = \frac{16}{144}

Cross multiply

10*144 = 16*x

1440 = 16x

Divide both sides by 16

90 = x

Area of the other polygon = 90 cm²

4 0
3 years ago
Please Help..........................
jasenka [17]
The exact circumference is 60ft
8 0
4 years ago
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I am not sure of the answers​
astra-53 [7]

Answer: 2 3/4 as an improper fraction would be B. 11/4

7 0
3 years ago
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Question 2 of 5
AlekseyPX

Given:

The different recursive formulae.

To find:

The explicit formulae for the given recursive formulae.

Solution:

The recursive formula of an arithmetic sequence is f(n)=f(n-1)+d, f(1)=a,n\geq 2 and the explicit formula is f(n)=a+(n-1)d, where a is the first term and d is the common difference.

The recursive formula of a geometric sequence is f(n)=rf(n-1), f(1)=a,n\geq 2 and the explicit formula is f(n)=ar^{n-1}, where a is the first term and r is the common ratio.

The first recursive formula is:

f(1)=5

f(n)=f(n-1)+5 for n\geq 2.

It is the recursive formula of an arithmetic sequence with first term 5 and common difference 5. So, the explicit formula for this recursive formula is:

f(n)=5+(n-1)(5)

f(n)=5+5(n-1)

Therefore, the correct option is A, i.e., f(n)=5+5(n-1).

The second recursive formula is:

f(1)=5

f(n)=3f(n-1) for n\geq 2.

It is the recursive formula of a geometric sequence with first term 5 and common ratio 3. So, the explicit formula for this recursive formula is:

f(n)=5(3)^{n-1}

Therefore, the correct option is F, i.e., f(n)=5(3)^{n-1}.

The third recursive formula is:

f(1)=5

f(n)=f(n-1)+3 for n\geq 2.

It is the recursive formula of an arithmetic sequence with first term 5 and common difference 3. So, the explicit formula for this recursive formula is:

f(n)=5+(n-1)(3)

f(n)=5+3(n-1)

Therefore, the correct option is D, i.e., f(n)=5+3(n-1).

6 0
3 years ago
Read 2 more answers
Evaluate: 3x + 6x for x=-1
bekas [8.4K]

Answer:

-9

Step-by-step explanation:

you put in -1 where there is an x in the equation

3(-1) + 6(-10)

-3 - 6

-9 is the answer

3 0
3 years ago
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