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masha68 [24]
3 years ago
13

What is the discriminant of the equation -4.9t^2+6.1t-0.8=0

Mathematics
1 answer:
vlabodo [156]3 years ago
8 0
\sqrt{6.1^2-4*-4.9*-0.8}  ≈ 4.64
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32 + 0.33c = p

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and p is the total price
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Which graph represents -x+ 8y > - 24
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Answer:

Step-by-step explanation:

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3 years ago
(I need the answer right now please) ΔA'B'C' was constructed using ΔABC and line segment EH. 2 triangles are shown. Line E H is
irina1246 [14]

Answer:

The true statements are

1. BD = DB'

3. m∠EFA = 90°

4. The line of reflection, EH, is the perpendicular bisector of BB', AA', and

   CC'

Step-by-step explanation:

* Lets explain how to solve the problem

- Reflection is flipping an object over the line of reflection.

- The object and its image have the same shape and size, but the

  figures are in opposite directions from the line of reflection

- The objects appear as if they are mirror reflections, with right and left

  reversed

- The line of reflection is a perpendicular bisector for all lines joining

  points on the figure with their corresponding images

- Look to the attached figure for more understand

* Lets solve the problem

- ΔA'B'C' was constructed using ΔABC and line segment EH, where

 EH is the reflection line

- D is the mid-point of BB'

- F is the mid-point of AA'

- G is the mid-point of CC'

* Lets find from the answer the true statements

1. BD = DB'

∵ D is the mid point of BB'

- Point D divides BB' into two equal parts

∴ BD = DB' ⇒ <em>True</em>

2. DF = FG

- It depends on the size of the sides and angles of the triangle

∵ We can't prove that

∴ DF = FG ⇒ <em>Not true</em>

3. m∠EFA = 90°

∵ The line of reflection ⊥ the lines joining the points with their

   corresponding images

∴ EH ⊥ AA' and bisect it at F

∴ m∠EFA = 90° ⇒ <em>True</em>

4. The line of reflection, EH, is the perpendicular bisector of BB',

   AA', and CC'

- Yes the line of reflection is perpendicular bisectors of them

∴ The line of reflection, EH, is the perpendicular bisector of BB',

   AA', and CC' ⇒ <em>True</em>

5. ΔABC is not congruent to ΔA'B'C'

∵ In reflection the object and its image have the same shape and size

∴ Δ ABC is congruent to Δ A'B'C'

∴ ΔABC is not congruent to ΔA'B'C' ⇒ <em>Not true</em>

4 0
3 years ago
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The diameter of a circle is 16 units.<br> What is the radius of the circle?
Licemer1 [7]

Answer:

radius is diameter over two

Step-by-step explanation:

so 16 divided by two will be 8

3 0
2 years ago
Which term could be put in the blank to create a fully simplified polynomial written in standard form?
Katena32 [7]

Correct Question:

Which term could be put in the blank to create a fully simplified polynomial written in standard form?

8x^3y^2 -\ [\ \ ] + 3xy^2 - 4y3

Options

x^2y^2            x^3y^3         7xy^2         7x^0y^3

Answer:

x^2y^2

Step-by-step explanation:

Given

8x^3y^2 -\ [\ \ ] + 3xy^2 - 4y^3

Required

Fill in the missing gap

We have that:

8x^3y^2 -\ [\ \ ] + 3xy^2 - 4y^3

From the polynomial, we can see that the power of x starts from 3 and stops at 0 while the power of y is constant.

Hence, the variable of the polynomial is x

This implies that the power of x decreases by 1 in each term.

The  missing gap has to its left, a term with x to the power of 3 and to its right, a term with x to the power of 1.

This implies that the blank will be filled with a term that has its power of x to be 2

From the list of given options, only x^2y^2 can be used to complete the polynomial.

Hence, the complete polynomial is:

8x^3y^2 -x^2y^2+ 3xy^2 - 4y3

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2 years ago
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