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Reil [10]
3 years ago
6

How do i graph the parabolas y = 1/32x^2

Mathematics
1 answer:
Pachacha [2.7K]3 years ago
7 0
y=\frac{1}{32}x^2 \\ \\x=-16 \Rightarrow  y=\frac{1}{32} *(-16)^2=\frac{1}{\not32^1}*\not256^8=8\\ \\x=-8 \Rightarrow  y=\frac{1}{32} *(-8)^2=\frac{1}{\not32^1}*\not64^2=2\\ \\x=0 \Rightarrow  y=\frac{1}{32} *(0)^2=\frac{1}{\not32^1}*0=0 \\ \\x=8 \Rightarrow  y=\frac{1}{32} *(8)^2=\frac{1}{\not32^1}*\not64^2=2 \\ \\x= 16 \Rightarrow  y=\frac{1}{32} *( 16)^2=\frac{1}{\not32^1}*\not256^8=8

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------------------------
</span>\left \{ {{3x + y = 9 } \atop {y = -4x + 10 }} \right.

Pass the incognito "4x" to the first term, changing the signal when changing sides.
<span>-------------------------
simplify by (-1)
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</span>\left \{ {{- 3x - \diagup\!\!\!\!y =-9} \atop {4x + \diagup\!\!\!\!y = 10}} \right.     &#10;
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</span>\left \{ {{- 3x = - 9} \atop {4x = 10}} \right.<span>

-----------
</span>\boxed{x = 1}<span><span>

</span></span><span>Substitute in equation (I) to find the value of "Y".

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Answer:
\boxed{\boxed{ \left \ {{x=1} \atop {y=6}} \right. }}

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