Answer:
![(x-1)^2+(y+4)^2=9](https://tex.z-dn.net/?f=%28x-1%29%5E2%2B%28y%2B4%29%5E2%3D9)
Step-by-step explanation:
The equation of a circle is given by:
![(x-h)^2+(y-k)^2=r^2](https://tex.z-dn.net/?f=%28x-h%29%5E2%2B%28y-k%29%5E2%3Dr%5E2)
Where (h, k) is the center and r is the radius.
The center of the circle is (1, -4).
And the radius is 3.
Substitute:
![(x-(1))^2+(y-(-4))^2=(3)^2](https://tex.z-dn.net/?f=%28x-%281%29%29%5E2%2B%28y-%28-4%29%29%5E2%3D%283%29%5E2)
Simplify. Thus, our equation is:
![(x-1)^2+(y+4)^2=9](https://tex.z-dn.net/?f=%28x-1%29%5E2%2B%28y%2B4%29%5E2%3D9)
Answer: see below
Step-by-step explanation:
(i)
200/2 = 100
Find 100 on cumulative frequency and the correspinding time: 14 minutes. So the answer is 14 minutes.
(ii)
First, find the lower quartile —> 200/4 = 50
Upper quartile —> 200/(3/4) = 150
Find the difference: 150 - 50 = 100
So the interquartile range is 100
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2x + 3y = -6 (Subtract 2x from both sides)
3y = -2x - 6 (Divide both sides by 3 to isolate x) which will give you y = -2/3x - 2 and this graphed would cross the x-axis at (-3,0) and the y-axis at (0, -2). So a + b = -5
I did it wrong the first time you're answer is b. 11*11^4