It seems it should be the other way... . How soon will the puppy catch up with the kitten.
The way you have it the kitten will never catch the pup. There is already 180m between them so, the distance will only increase because the puppy runs faster than the cat.
If the puppy runs after the cat, will eventually catch up with it and can be calculated. Not the other way around.
If the pup runs after the cat, the distance between them will decrease and the pup will catch the cat.
RT = D kitten
RT = D+180 puppy
20T = D
25T = D + 180
Substitution
25T = 20T +180
5T = 180
T = 36s
28% decrease
Solution:
Calculate percentage change
from V1 = 25 to V2 = 18
(V2−V1)|V1|×100
=(18−25)|25|×100
=−725×100
=−0.28×100
=−28%change
=28%decrease
Answer:
66 sunny days before birthday
Step-by-step explanation:
Total sunny days after birthday = 17
Total sunny days in year = 83
Birthday was not sunny
Total sunny days before birthday = 83 -17
= 66 sunny days
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Answer:
c. y = -35*x + 105
Step-by-step explanation:
Lo que demos hacer es calcular los puntos cuando x = 0 y cuando x = 3, es decir el inicio y el fin del recorrido.
Cuando x es igual 0, y = 105, por lo tanto, la función sería:
y = A*x + 105
Cuando x = 3, y = 0, por lo tanto:
0 = 3*A + 105
resolvemos para A:
3*A = -105
A = -105/3
A = -35
Por lo tanto la función es:
y = -35*x + 105
es decir, la opción c.
Any number above 1 gets greater, below 1 smaller (when above 0), while 1 itself remains the same. Negative numbers are more unpredictable.
