Answer:
All shapes except the cone with 5in radius and 8in height
Step-by-step explanation:
Volume of the cylinder with radius 5in and height 8in is expressed as;
V = πr²h
V = 3.14*5²*8
V = 3.14*25*8
V = 628 square inches
The volume of the cylinder is greater than 500in³
Volume of the cone with radius 5in and height 24in is expressed as;
V = 1/3πr²h
V = 1/3*3.14*5²*24
V = 3.14*25*8
V = 628 square inches
The volume of the cone is greater than 500in³
Volume of the spheree with radius 5in is expressed as;
V = 4/3πr³
V = 4/3π(5)³
V = 4/3 * 3.14 * 125
V = 523.33 square inches
The volume of the sphere is greater than 500in³
65 millimeters to meters is .065 and you would know this because there's .001 millimeters in 1 meter so with 65 you would move the decimal up 3 spaces o make .065m
Answer:
x= 2
Step-by-step explanation:
3x – 5 = 1
Add 5 to each side
3x – 5+5 = 1+5
3x = 6
Divide by 3
3x/3 = 6/3
x= 2
Answer:
The solution is similar to the 2-point form of the equation for a line:
y = (y2 -y1)/(x2 -x1)·x + (y1) -(x1)(y2 -y1)/(x2 -x1)
Step-by-step explanation:
Using the two points, write two equations in the unknowns of the equation of the line.
For example, you can use the equation ...
y = mx + b
Then for the points (x1, y1) and (x2, y2) you have two equations in m and b:
b + (x1)m = (y1)
b + (x2)m = (y2)
The corresponding augmented matrix for this system is ...
![\left[\begin{array}{cc|c}1&x1&y1\\1&x2&y2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Cc%7D1%26x1%26y1%5C%5C1%26x2%26y2%5Cend%7Barray%7D%5Cright%5D)
____
The "b" variable can be eliminated by subtracting the first equation from the second. This puts a 0 in row 2 column 1 of the matrix, per <em>Gaussian Elimination</em>.
0 + (x2 -x1)m = (y2 -y1)
Dividing by the value in row 2 column 2 gives you the value of m:
m = (y2 -y1)/(x2 -x1)
This value can be substituted into either equation to find the value of b.
b = (y1) -(x1)(y2 -y1)/(x2 -x1) . . . . . substituting for m in the first equation
Answer:
5 minutes
Step-by-step explanation:
To find the number of minutes it takes Jason to run a mile, we have to first find the rate at which he runs.
This is called Jason's speed. It is given as


From the formula of speed, time is given as:

Time taken for Jason to run 1 mile (1760 yards) will therefore be:

Converting this time to minutes yields:
60 seconds = 1 minute
300.34 equals:

It takes Jason 5 minutes to run 1 mile.