Question:
Solution:
Let the following equation:
![\sqrt[]{12-x}=\text{ x}](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B12-x%7D%3D%5Ctext%7B%20x%7D)
this is equivalent to:
![(\sqrt[]{12-x})^2=x^2](https://tex.z-dn.net/?f=%28%5Csqrt%5B%5D%7B12-x%7D%29%5E2%3Dx%5E2)
this is equivalent to:

this is equivalent to:

thus, we can conclude that
x= 3.
Answer:
i have no idea.
Step-by-step explanation:
Answer:
x = 4
Step-by-step explanation:
Answer: x= 2
Step-by-step explanation:
hope this helped :)
First, pull out the GCM from the two terms: 3x^6(x^3-64)
Then factor the remains using the difference of cubes: 3x^6(x-4)(x^2+4x+16)