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VMariaS [17]
3 years ago
13

If y=3x+1 were changed to y=x+1 how would the graph of the new function compare with the original?

Mathematics
1 answer:
Olegator [25]3 years ago
5 0
F(x)=3x+1  (preimage)
g(x)=x+1  (image)
it is undergoing a reduction/compression with translation.
In general, a linear transformation is
g(x) = a*f(bx-h)+k
h=horizontal translation (right if h>0, left if h<0, note formula has minus sign)
k=vertical translation (up if k>0, down if k<0)
a=vertical stretching, (stretching if |a|>1, compression if |a|<1, also, if a<0, a reflection across the x-axis is performed)
b=horizontal stretching (|b|>0 compression, |b|<0 stretching, also, if b<0, a reflection across the y-axis is performed)

In this case, 
g(x)=f(x/3), so it is a horizontal stretching.
Note that the y-intercept remains unchanged.
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If you roll two fair six-sided dice, what is the probability that both dice show an odd number?
OLEGan [10]

Answer:

1/4

Step-by-step explanation:

Both dice have odd numbers 1, 3, 5. The chances of getting an odd number on each number is 3/6

The probability of getting odd numbers on both is:

3/6 ⋅ 3/6 = 9/36 = 1/4

5 0
3 years ago
Read 2 more answers
a company that manufactures and ships canned vegetables is designing boxes in the shape of rectangular prisms to meet specific r
sertanlavr [38]
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a = 3 · 3 = 9in
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Now, you can calculate the total surface area:
A = 2</span>·(a·b + a·h + b·h)
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7 0
3 years ago
(1) In the diagram below, AC || DF|| BH || and CB || FE.
Liula [17]

Answer:

Part 1) Triangles ABC, DBG, DEF and BEH are similar

Part 2) \frac{AB}{AC}=\frac{DE}{DF}=\frac{DB}{DG}=\frac{BE}{BH}

Step-by-step explanation:

Part 1)

we know that    

If two triangles are similar, then the ratio of its corresponding sides is equal and its corresponding angles are congruent

In this problem Triangles ABC, DBG, DEF and BEH are similar, because its corresponding angles are congruent by AA Similarity Theorem

Part 2)

Remember that

If two triangles are similar, then the ratio of its corresponding sides is equal

therefore

\frac{AB}{AC}=\frac{DE}{DF}=\frac{DB}{DG}=\frac{BE}{BH}

5 0
3 years ago
Read 2 more answers
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