Answer:
a) The mean of the data set is $33,691.13 and can be calculated by finding the average of the sum of the eight salaries.
b) The five number of the data set is {27,274; 30,421; 32,941.5; 35,682; 44,166} and can be calculated by finding the minimum, maximum, median, and interquartile range values.
c) The standard deviation of the data set is 4773.50 and can be calculated by finding the square root of the average of the sum of the differences from the mean squared.
Answer:
1 1/2 I think either that are the other way around
I'll use t for the messages Teresa sent, e for messages Eric sent, and r for messages Ryan sent.
Therefore we have, t+e+r=99.
From the text we also know:
e=3r ; r=t+6
If we substitute in the original equation we get:
t+3(t+6)+t+6=99; By simplifying it we get
5t=75 , therefore t=75/5=15.
Since Teresa send 15 messages,Ryan sent 6 more then here, so he send 21. Eric sent three times the
messages Ryan sent so he sent 63 messages. If we add them together 15+21+63, we get the total of 99 messages.
1 Metre is the length of each side of the cube.
To example, here is the Volume Of Cube Equation:
V = a^3
We are given the value for V, so just take the cube root of 1, which equates to 1.
Answer:
Mason has
- 16 20¢ stamps;
- 25 3¢ stamps;
- 40 49¢ stamps.
Step-by-step explanation:
Let x be the number of 20¢ stamps, then the number of 3¢ stamps is x + 9.
Mason has 56 total 49¢ and 20¢ stamps, then the number of 49¢ stamps is 56 - x.
Amounts:
- in 49¢:
cents; - in 20¢:
cents; - in 3¢:
cents.
Total amount:
- $23.55.
Hence,
Mason has
- 16 20¢ stamps;
- 25 3¢ stamps;
- 40 49¢ stamps.
