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Vadim26 [7]
3 years ago
12

I need help on this question pls answer :(

Mathematics
1 answer:
Oxana [17]3 years ago
6 0

Answer:

Option 3

Step-by-step explanation:

Given functions are,

f(x) = \frac{1}{x-3}

g(x) = \sqrt{x+5}

Therefore, composite function (f o g) will be,

(f o g)(x) = f[g(x)]

             = \frac{1}{\sqrt{x+5} -3}

This function will be defined for,

Denominator > 0

\sqrt{x+5}-3>0

\sqrt{x+5} >3

(x+5)>3^2

x+5>9

x>9-5

x>4

And x+5\geq 0

x\geq -5

Therefore, domain of the composite function will be,

[-5, 4) ∪ (4, ∞)

Option 3 will be the answer.

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The net of a pyramid is shown below.
sveticcg [70]

Answer:

80 in^2

Step-by-step explanation:

8*4=32

32/2=16

16= One triangle

16*4 triangles=64

4*4=16

64+16=80

8 0
3 years ago
June had $240 more than Siti. Junr gave 25% of her money to Siti. Siti then gave 20% of her money to June. How much more money d
bulgar [2K]

Answer:

$144

Step-by-step explanation:

Let the money which Siti has be x

Therefore, the money June has will be x+240

First condition is that June gave 25% of her money to Siti, So this amount will be deducted from June's money and will be added in Siti's money.

Siti's money = x+ [25%(x+240)]       June's money = x+240-[25%(x+240)]

                   = 1.25x + 60                                       = 0.75x + 180

Second condition is that Siti now gave 20% of her money to June.This amount will be deducted form Siti's money and added in June's money.

Siti's money = 1.25x+60-[20%(1.25x+60)]    

                    = x+48

June's money = 0.75x +180+[20%(1.25x+60)]

                        = x+192

Difference between Sitit and June's money = x+192-x-48

                                                                        = 144

Hence, June has $144 more money than Siti.

4 0
3 years ago
If 8n+22=70 find the value of 3n
kondaur [170]
8n + 22 = 70

-22          -22


8n = 48
n = 48/8

n = 6


n*3 = 3n = 6*3 = 18


3n = 18
6 0
3 years ago
Read 2 more answers
A cube has a volume of 2197 m^3. Its surface is to be painted. Each can of paint covers about 40 m^2. How many cans of paint are
Gelneren [198K]
<em>Volume= a³</em>
<em>a=edge</em>
<em>2197 = a³</em>
<em>=> a=13 m</em>
<em>Surface area=6a²=6*13²=6*169=1014 m²</em>
<em>\frac{1014}{40} = 25,35 ≈ 26</em>
<em>=> <u>26 cans needed</u></em>
8 0
3 years ago
I need details on how to solve this problem please
Radda [10]

I hope I answer your question

7 0
3 years ago
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