Answer:
The area of triangle for the given coordinates is 1.5
Step-by-step explanation:
Given coordinates of triangles as
A = (0,0)
B = (3,4)
C = (3,2)
So, The measure of length AB = a = 
Or, a = 
Or, a = 
Or, a = 
∴ a = 5 unit
Similarly
The measure of length BC = b =
Or, b = 
Or, a = 
Or, b = 
∴ b = 2 unit
And
So, The measure of length CA = c =
Or, c = 
Or, c = 
Or, c = 
∴ c = unit
Now, area of Triangle written as , from Heron's formula
A = 
and s = 
I.e s = 
Or. s = 
So, A = 
Or, A = 
Or, A = 
× 
∴ Area of triangle = 1.5
Hence The area of triangle for the given coordinates is 1.5 Answer
First, you have to substitute for x, which would make the problem f(x)=7.45(-4.3)+33.7
Now, you just have to use the PEMDAS method (Parenthesis, Exponents, Multiplication, Division, Addition, Subtraction)
f(x)= -32.035+33.7
f(x)=1.665
Answer:
b=-7
Step-by-step explanation:
Simplifying
99 = 2(-7b + -3) + 7
Reorder the terms:
99 = 2(-3 + -7b) + 7
99 = (-3 * 2 + -7b * 2) + 7
99 = (-6 + -14b) + 7
Reorder the terms:
99 = -6 + 7 + -14b
Combine like terms: -6 + 7 = 1
99 = 1 + -14b
Solving
99 = 1 + -14b
Solving for variable 'b'.
Move all terms containing b to the left, all other terms to the right.
Add '14b' to each side of the equation.
99 + 14b = 1 + -14b + 14b
Combine like terms: -14b + 14b = 0
99 + 14b = 1 + 0
99 + 14b = 1
Add '-99' to each side of the equation.
99 + -99 + 14b = 1 + -99
Combine like terms: 99 + -99 = 0
0 + 14b = 1 + -99
14b = 1 + -99
Combine like terms: 1 + -99 = -98
14b = -98
Divide each side by '14'.
b = -7
Simplifying
b = -7
Answer:
a) 48.21 %
b) 45.99 %
c) 20.88 %
d) 42.07 %
e) 50 %
Note: these values represent differences between z values and the mean
Step-by-step explanation:
The test to carry out is:
Null hypothesis H₀ is μ₀ = 30
The alternative hypothesis m ≠ 30
In which we already have the value of z for each case therefore we look directly the probability in z table and carefully take into account that we had been asked for differences from the mean (0.5)
a) z = 2.1 correspond to 0.9821 but mean value is ubicated at 0.5 then we subtract 0.9821 - 0.5 and get 0.4821 or 48.21 %
b) z = -1.75 P(m) = 0.0401 That implies the probability of m being from that point p to the end of the tail, the difference between this point and the mean so 0.5 - 0.0401 = 0.4599 or 45.99 %
c) z = -.55 P(m) = 0.2912 and this value for same reason as before is 0.5 - 0.2912 = 0.2088 or 20.88 %
d) z = 1.41 P(m) = 0.9207 0.9207 -0.5 0.4207 or 42.07 %
e) z = -5.3 P(m) = 0 meaning there is not such value in z table is too small to compute and difference to mean value will be 0.5
d) z= 1.41 P(m) =
