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2 years ago

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Which set of ordered pairs is a linear function?O A) (-2, -1), (0, 1), (2, 1), (4, 1)O B) 12, 1), (0,1), (2, 1), (4,-1)O C (-2,

-1), (0, 1), (2,-1), (4, 1)O D (-2, 1), (0, 1), (2, 1), (4, 1)

1 answer:

atroni [7]2 years ago

5 0

I think A is you answer.

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tino4ka555 [31]

Answer:

x=2

Step-by-step explanation:

x+2=4

x=2

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Arianna gathered data about the distance of 20 cities from the equator and the average hours of sunlight per day in December for

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<u>Answer-</u>

<em>A. strong negative correlation.</em>

<u>Solution-</u>

<u>Direction of a relationship</u>

Positive- If one variable increases, the other tends to also increase. If one decreases, the other tends to also. It is represented by positive numbers(i.e 0 to 1).
Negative- If one variable increases, the other tends to decrease, and vice-versa. It is represented by negative numbers(i.e 0 to -1)

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As in this case, correlation coefficient was found to be -0.91, which is negative and close to -1, so it is a strong negative correlation.

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3 years ago

Which graph shows g(x)=4x−4−8 ?

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3 years ago

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Answer:

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2 years ago

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A rancher wants to fence in an area of 1500000 square feet in a rectangular field and then divide it in half with a fence down t

VLD [36.1K]

Answer:

6000 ft

Step-by-step explanation:

Let length of rectangular field=x

Breadth of rectangular field=y

Area of rectangular field= $1500000$ square ft

Area of rectangular field= $l\times b$

Area of rectangular field= $x\time y$

$1500000=xy$

$y=\frac{1500000}{x}$

Fencing used ,P(x)= $x+x+y+y+y=2x+3y$

Substitute the value of y

P(x)= $2x+3(\frac{1500000}{x})$

$P(x)=2x+\frac{4500000}{x}$

Differentiate w.r.t x

$P'(x)=2-\frac{4500000}{x^2}$

Using formula: $\frac{dx^n}{dx}=nx^{n-1}$

$P'(x)=0$

$2-\frac{4500000}{x^2}=0$

$\frac{4500000}{x^2}=2$

$x^2=\frac{4500000}{2}=2250000$

$x=\sqrt{2250000}=1500$

It is always positive because length is always positive.

Again differentiate w.r.t x

$P''(x)=\frac{9000000}{x^3}$

Substitute x=1500

$P''(1500)=\frac{9000000}{(1500)^3}>0$

Hence, fencing is minimum at x=1 500

Substitute x=1 500

$y=\frac{1500000}{1500}=1000$

Length of rectangular field=1500 ft

Breadth of rectangular field=1000 ft

Substitute the values

Shortest length of fence used= $2(1500)+3(1000)=6000 ft$

Hence, the shortest length of fence that the rancher can used=6000 ft

3 0

3 years ago