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1 year ago

Maths functions question

Mathematics

2 answers:

ahrayia [7]1 year ago

5 0

The final question is asking for where the line is higher than the curve which is between D and A
We know the x coordinates of these so the answer is
-4

il63 [147K]1 year ago

3 0

Answer:

-4 < x < 3

Step-by-step explanation:

<u>Information from Parts 1-4 of the same question:</u>

brainly.com/question/28193969

$f(x)=-x+3$

$g(x)=x^2-9$

A = (3, 0)

<u>Information from Parts 5-8 of the same question:</u>

brainly.com/question/28193994

D = (-4, 7)

The values of x for which g(x) < f(x) are the values of x between the points of intersection of the two functions: points D and A.

From part (2) of the question, we found that A = (3, 0).

From part (5) of the question, we found that D = (-4, 7).

Therefore, the values of x for which g(x) < f(x) are -4 < x < 3.

In interval notation this is: (-4, 3).

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Simplify the Expression

nlexa [21]

Answer:

$125a^{3}b^{2}$

Step-by-step explanation:

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2 years ago

A community organizes a phone tree in order to alert each family of emergencies. In the first stage, one person calls five famil

Lady_Fox [76]

Basically you are multiplying each thing by 5
1 stage 1
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2 years ago

Read 2 more answers

Express the integral as a limit of Riemann sums. Do not evaluate the limit. (Use the right endpoints of each subinterval as your

Darina [25.2K]

Answer:

Given definite integral as a limit of Riemann sums is:

$\lim_{n \to \infty} \sum^{n} _{i=1}3[\frac{9}{n^{3}}i^{3}+\frac{36}{n^{2}}i^{2}+\frac{97}{2n}i+22]$

Step-by-step explanation:

Given definite integral is:

$\int\limits^7_4 {\frac{x}{2}+x^{3}} \, dx \\f(x)=\frac{x}{2}+x^{3}---(1)\\\Delta x=\frac{b-a}{n}\\\\\Delta x=\frac{7-4}{n}=\frac{3}{n}\\\\x_{i}=a+\Delta xi\\a= Lower Limit=4\\\implies x_{i}=4+\frac{3}{n}i---(2)\\\\then\\f(x_{i})=\frac{x_{i}}{2}+x_{i}^{3}$

Substituting (2) in above

$f(x_{i})=\frac{1}{2}(4+\frac{3}{n}i)+(4+\frac{3}{n}i)^{3}\\\\f(x_{i})=(2+\frac{3}{2n}i)+(64+\frac{27}{n^{3}}i^{3}+3(16)\frac{3}{n}i+3(4)\frac{9}{n^{2}}i^{2})\\\\f(x_{i})=\frac{27}{n^{3}}i^{3}+\frac{108}{n^{2}}i^{2}+\frac{3}{2n}i+\frac{144}{n}i+66\\\\f(x_{i})=\frac{27}{n^{3}}i^{3}+\frac{108}{n^{2}}i^{2}+\frac{291}{2n}i+66\\\\f(x_{i})=3[\frac{9}{n^{3}}i^{3}+\frac{36}{n^{2}}i^{2}+\frac{97}{2n}i+22]$

Riemann sum is:

$= \lim_{n \to \infty} \sum^{n} _{i=1}3[\frac{9}{n^{3}}i^{3}+\frac{36}{n^{2}}i^{2}+\frac{97}{2n}i+22]$

4 0

2 years ago

The length of the rectangle is three more than the width find the length of the rectangle if the perimeter is 98 inches

Aleks [24]

Answer:

length is 26 and width is 23

Step-by-step explanation:

let width be x

then length is 3+x since it is 3 more than the width

perimeter of a rectangle = 2l + 2w

98=2 [3+x] + 2x

98=6+2x+2x

98=6+4x

98-6=4x

92=4x

x=23

width is 23 and

breadth is 26

5 0

2 years ago

ASAP!! ILL GIVE BRAINLEST

Alex

I think A^3:B^

Explanation:

It is 3 dimensional, so the surface area would be 3x bigger, so A^3:B^

5 0

2 years ago