Question

Suppose a normal distribution has a mean of 266 and a standard deviation of

Answer 1

Answer:

P(x>278) is 0.16

Step-by-step explanation:

We are given that a normal distribution has a mean of 266 and a standard deviation of  12.

Mean = $\mu =266$

Standard deviation =$\sigma = 12$

We are supposed to find P(x > 278)

So, Formula : $Z=\frac{x-\mu}{\sigma}$

$Z=\frac{278-266}{12}$

Z=1

Refer the z table for p value

p value = 0.8413

P(x<278) is 0.84

P(x>278)=1-P(x<278)=1-0.84=0.16

Option A is true

Hence P(x>278) is 0.16