How much would $400 be worth after 16 years, if it were invested at 3% interest compounded annually? (Use the formula below and round your answer to the nearest cent.) A(t)=P(1+ r/n)^nt
1 answer:
Your Principal, P, is $400. Your interest rate, expressed as a decimal, is 0.03. Here, n is 1, since there is just 1 compounding period per year. How much would you have after 16 years under such circumstances? A = Amount = $400(1+0.03)^16. => $400 (1.03)^16 = $400(1.60) Thus, you would have accumulated $641.88 after 16 years. Sounds like a pretty good deal to me. ;)
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Well if 100%= $8.05 then to find 10% you divide by 100. 10%=$0.85 You would then take this off of your original price. This is how I like to lay mine out: 100%=$8.05 - 10%=$0.85 = 90%=$7.20 Therefore 90% of $8.05 is $7.20
Answer:
7
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2x_(_5x)
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Answer:
the correct answer would be B.
ANSWER: y=9
First substitute x
6.4(3)+2.8y=44.4
19.2+2.8y=44.4
subtract 19.2 from both sides
2.8y=25.2
divide by 2.8 on both sides
y=9
Answer: 60 cm
Step-by-step explanation:
3/5 = 0.60
0.60(100) = cm
60 = cm