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vichka [17]
2 years ago
8

The graphs below have the same shape. What is the equation of the blue graph?

Mathematics
1 answer:
Yanka [14]2 years ago
7 0

Answer:

B. G(x)=(x-2)^2 + 1

Step-by-step explanation:

the graph shifts two to the right x^2 turns into (x-2)^2

and the y value shifts from 0 to 1 (+1)

together, we get (x-2)^2 + 1

:)

You might be interested in
Which pair of triangles can be proven congruent by SAS?
ivolga24 [154]

Answer:

Second option

Step-by-step explanation:

They have two congruent pairs of sides and one congruent pair of angles.

4 0
2 years ago
The perimeter of a rectangle is 102 inches. The length is 5 inches greater than the width.
Mazyrski [523]

Answer:

w = 23

l = 28

Step-by-step explanation:

w = width

l = w+5

P = 2 (l+w)

102 = 2( w+5+w)

102 = 2(2w+5)

Divide each side by 2

51 = 2w+5

Subtract 5

46 = 2w

Divide by 2

23 = w

The width is 23 and the length is 23+5 = 28

5 0
3 years ago
Read 2 more answers
I seem to be confused can anyone please help
Genrish500 [490]
Use photo math :>some helpful info
6 0
3 years ago
A skier has decided that on each trip down a slope, she will do 3 more jumps than before. On her first trip she did 5 jumps. Der
taurus [48]
Since we are already given the amount of jumps from the first trial, and how much it should be increased by on each succeeding trial, we can already solve for the amount of jumps from the first through tenth trials. Starting from 5 and adding 3 each time, we get: 5 8 (11) 14 17 20 23 26 29 32, with 11 being the third trial.

Having been provided 2 different sigma notations, which I assume are choices to the question, we can substitute the initial value to see if it does match the result of the 3rd trial which we obtained by manual adding.

Let us try it below:

Sigma notation 1:

  10
<span>   Σ (2i + 3)
</span>i = 3

@ i = 3

2(3) + 3
12

The first sigma notation does not have the same result, so we move on to the next.

  10
<span>   Σ (3i + 2)
</span><span>i = 3
</span>
When i = 3; <span>3(3) + 2 = 11. (OK)
</span>
Since the 3rd trial is a match, we test it with the other values for the 4th through 10th trials.

When i = 4; <span>3(4) + 2 = 14. (OK)
</span>When i = 5; <span>3(5) + 2 = 17. (OK)
</span>When i = 6; <span>3(6) + 2 = 20. (OK)
</span>When i = 7; 3(7) + 2 = 23. (OK)
When i = 8; <span>3(8) + 2 = 26. (OK)
</span>When i = 9; <span>3(9) + 2 = 29. (OK)
</span>When i = 10; <span>3(10) + 2 = 32. (OK)

Adding the results from her 3rd through 10th trials: </span><span>11 + 14 + 17 + 20 + 23 + 26 + 29 + 32 = 172.
</span>
Therefore, the total jumps she had made from her third to tenth trips is 172.


3 0
3 years ago
I need help with number 9
Westkost [7]

Answer:

A) A dilation followed by a reflection.

Step-by-step explanation:

I went over this in class the other day.    (:

7 0
3 years ago
Read 2 more answers
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