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Talja [164]
3 years ago
13

3. What is the average (arithmetic mean) of all the multiples of ten from 10 to 190 inclusive?

Mathematics
2 answers:
viktelen [127]3 years ago
8 0
Hello!

The average mean (arithmetic mean) of all the multiples of ten from 10 to 190 inclusive would be C. 100.

Explanation:

10 and 190 inclusive would mean that there are 19 terms.

To find the arithmetic mean, we must add all the numbers and divide by the amount of numbers.

If you add up all the terms, you will get 1,900. Now, divide that by the number of terms.

1,900 ÷ 19 = 100

Therefore, your answer is C. 100.

Have a wonderful day!
Sergio039 [100]3 years ago
7 0

Answer:

100

Step-by-step explanation: 100

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your answer should be true if you put parenthesis!

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The probability that the customer must open 3 or more bottles before finding a prize is 0.64

Step-by-step explanation:

In order for a customer to have to open at least 3 bottles before winning a prize, then the first two bottles shouldnt have a price. The probability that a bottle doesnt have a price is 1-0.2 = 0.8. Since the bottles are independent from each other, then the probability that 2 bottles dont have a prize is 0.8² = 0.64. Therefore, the probability that the customer must open 3 or more bottles before finding a prize is 0.64

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The length of shadow decrease at 0.48 m/s.

Step-by-step explanation:

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Now solve for the dy/dt when x=4

from the diagram (triangle) it can be seen similar triangles with similar base/height ratios.

\frac{2}{12-x} = \frac{y}{12} \\Y = \frac{24}{12 - x} \\ \frac{dy}{dt} = \frac{24}{(12-x)^{2}} \times \frac{dx}{dt} \\at x=4, dy/dt \ becomes: \\\frac{24}{(12-4)^2} \times -1.3 \\= -0.48 m/s

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Every day for 5 days Jack and Jill went walking. Each day Jack walked 4/5 of a mile and Jill walked 2/3 of a mile. At the end of
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\\\\[-0.35em]
~\dotfill\\\\
\cfrac{28}{5}-\cfrac{14}{3}\implies \stackrel{\textit{LCD of 15}}{\cfrac{(3)28-(5)14}{15}}\implies \cfrac{84-70}{15}\implies \cfrac{14}{15}

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