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Talja [164]
3 years ago
13

3. What is the average (arithmetic mean) of all the multiples of ten from 10 to 190 inclusive?

Mathematics
2 answers:
viktelen [127]3 years ago
8 0
Hello!

The average mean (arithmetic mean) of all the multiples of ten from 10 to 190 inclusive would be C. 100.

Explanation:

10 and 190 inclusive would mean that there are 19 terms.

To find the arithmetic mean, we must add all the numbers and divide by the amount of numbers.

If you add up all the terms, you will get 1,900. Now, divide that by the number of terms.

1,900 ÷ 19 = 100

Therefore, your answer is C. 100.

Have a wonderful day!
Sergio039 [100]3 years ago
7 0

Answer:

100

Step-by-step explanation: 100

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It is given in the question that

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Let the price of scanner be $ x .

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It means , the price should be not more then $70 .

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Two bumper cars are the EXACT SAME MASS and collide into each other's front bumper while traveling at the EXACT SAME VELOCITY. E
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Answer:

the effect

Step-by-step explanation:

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3 years ago
I am trying to help my grandson understand comparing the value of underlined digits. Such as 40 and 400
LenaWriter [7]

Answer:

The value of 4 in 400 is 10 times the value of 4 in 40.

Step-by-step explanation:

Given :  40 and 400.

To find : compare the values of the underlined digits .

Solution : We have given  40 and 400.

In 400

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In 40

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The value of 4 in 40 is 4 tens.

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Therefore, The value of 4 in 400 is 10 times the value of 4 in 40.

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4 years ago
Arrange the reasons for the proof in the correct order. Prove: If the diameter of a circle is 6 meters and the formula for diame
Misha Larkins [42]
Given the question: Arrange the reasons for the proof in the correct order. Prove: If the diameter of a circle is 6 meters and the formula for diameter is d = 2r, then the radius of the circle is 3 meters.
A. If r ≠ 3 m, then d ≠ 6 m. Since the contrapositive is true, the original statement must also be true. Therefore, if the diameter of a circle is 6 meters, then the radius is 3 meters.
B. Multiplication of real numbers shows that d = 2(2 m) = 4 m.
C. Substitute r = 2 m into d = 2r.
D. Assume that r ≠ 3 m. For example, the radius equals another length, such as r = 2 m.

To prove that i<span>f the diameter of a circle is 6 meters and the formula for diameter is d = 2r, then the radius of the circle is 3 meters by contradiction, we assume that the radius in not equal to 3 meters, for </span>example, the radius equals another length, such as r = 2 m.
Next, we substitute the value: r = 2m nto the original equation that says that d = 2r, i.e. d = 2(2m) = 4m which is not true and contradicts the original statement that the diameter of the circle is 6m.

Therefore, the arrangement of the proof is as follows:
 D. Assume that r ≠ 3 m. For example, the radius equals another length, such as r = 2 m.
C. Substitute r = 2 m into d = 2r.
B. Multiplication of real numbers shows that d = 2(2 m) = 4 m.
A. If r ≠ 3 m, then d ≠ 6 m. Since the contrapositive is true, the original statement must also be true. Therefore, if the diameter of a circle is 6 meters, then the radius is 3 meters.

D C B A.
3 0
3 years ago
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