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umka21 [38]
3 years ago
13

How much work (in joules) is done in moving a charge of 2.5 _C a distance of 53 cm along an equipotential at 10 V? I got -2.25e-

5 is this correct?
Mathematics
1 answer:
stiv31 [10]3 years ago
5 0
Since the field is equipotential. Thus, change in potential is 0 and thus
Work = charge x change in potential = 2.5 x 10^-6 x 0 = 0.

Requires work is 0 joules.
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What is the value of this expression? 6 (24÷ 3) - 2​
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Answer:

6 (24÷3) -2

6 (8) -2

48-2

=46

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Is 18 and 0.3 equivalent
grigory [225]

Answer:

No

Step-by-step explanation:

Because 0.3 is a decimal and 18 is a whole number.

0.3 = 3/10 which is 30%

5 0
3 years ago
On a coordinate plane, triangles R S T and L M N are shown. Triangle R S T has points (5, 5), (2, 1), and (1, 3). Triangle L M N
ivolga24 [154]

Answer:

LMN has a larger area

Step-by-step explanation:

Given

RST

R =(5,5)

S= (2,1)

T = (1,3)

LMN

L = (0,-1)

M= (2,-4)

N= (-2,-3)

Required

Compare both areas

The area of triangle is:

Area = \frac{1}{2}|x_1y_2 - x_2y_1 + x_2y_3 - x_3y_2 + x_3y_1 - x_1y_3|

For RST, we have:

Area = \frac{1}{2}|5*1 - 2*5 + 2*3 - 1*1 + 1*5 - 5*3|

Area = \frac{1}{2}|-10|

Remove absolute signs

Area = \frac{1}{2}*10

Area = 10

For LMN, we have:

Area = \frac{1}{2}|x_1y_2 - x_2y_1 + x_2y_3 - x_3y_2 + x_3y_1 - x_1y_3|

Area = \frac{1}{2}|0*-4-2*-1+2*-3--2*-4--2*-1-0*-3|

Area = \frac{1}{2}|-14|

Remove absolute signs

Area = \frac{1}{2}*14

Area = 7

<em>By comparing both areas, we can conclude that LMN has a larger area</em>

3 0
2 years ago
Solve:
svlad2 [7]
Hello!

Judging on the questions you have provided I have come to the conclusion that to solve all of these you need to find the value of x by isolating it all on one side and simplifying.

For question #1 the first step would be to subtract 6 from each side.
The outcome should be -x=-6-12, and if simplified -x=-18.
Next, you want to divide each side by -1 because x needs to always be positive when finding the solution.
Your answer for #1 should be X=18, D.

For question #2 the first step you should take is to subtract 1.33 from each side to isolate x. 
The outcome should be x=7.82-1.33, and if simplified x=6.49.
Thus your answer for #2 should be X=6.49, A.

For question #3 the first step you should take to approaching the equation is to isolate x by adding 15.99 towards each side of the equation.
The outcome should be x=58.06+15.99, and if simplified x=74.05.
Thus your answer for question #3 should be X=74.05, D.

Lastly, for question #4 the first step you should take towards isolating x is to divide the entire equation by 1.32.
Your outcome should be x= 6.8
Thus, your answer for the last question, #4, should be X=6.8, C.

Hope this helped!
-Blake
8 0
2 years ago
Read 2 more answers
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