The sum of the angles of a quadrilateral is 360 degrees. So P+Q+R is 206, 360 - 206 = 154 degrees, the measure of angle S.
The four triangles, AQB, BRC, CSD, and DPA are all isosceles. So angle QBA = angle BAQ, etc. We find QBA = (180-24)/2 or 78 degrees.
RBC = (180-114)/2 = 33 degrees.
180 - (78 + 33) is the measure of angle B: 69 degrees.
The student should be able to see how to calculate the missing information from this.
Answer=10%
15+2+3=20
2 of which are blue.
Put it over 100, 20x5=100 so 2x5=10
Answer:
60
The angle acute so my guess is 60
Hope this helps :)
Answer:
n to the power of -2
Step-by-step explanation:
i counted all the others and this is the only one that doesn't add up to 16. the last answer is -16 not 16 so there you go.
Don't panic! The answer is 42.
But it looks like you did not copy the full question.
