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Lostsunrise [7]
3 years ago
13

The total length of rope, in feet, used to put up tents is 60 times the number of tents

Mathematics
2 answers:
harina [27]3 years ago
7 0
The total length of rope = r

is 60 times
the number of tents = t
r = 60t
solmaris [256]3 years ago
4 0

Answer:

Total length of the rope = 6x  feet.

Step-by-step explanation:

Given  : The total length of rope, in feet, used to put up tents is 60 times the number of tents

To find : Total length of the rope.

Solution: We have given  

Let the number = x

Tenth of the number = \frac{x}{10}.

According to question :

60 times the number of the tenths.

60 *  \frac{x}{10}.

Total length of the rope = 60 *  \frac{x}{10}.

Total length = 6 x .

Therefore, Total length of the rope = 6x feet .

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LenaWriter [7]
X= 2 hope this helped
6 0
2 years ago
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Simplify (-8)(-2) + 11<br> 027<br> 0 -1<br> 0-5
Schach [20]
Answer:-5
-8x-2=-16
-16+11=-5
4 0
3 years ago
Sal made 8 ft of sausage links on Friday morning. He used 4 ft for dinner service on Friday night. On Saturday morning, he made
oee [108]

Answer:

Net change in the amount of sausage Sal had from Friday morning until after dinner service Saturday night = 8 - 0 = 8 ft

Step-by-step explanation:

Amount of  sausage links made on Friday morning = 8 ft

Amount of  sausage links used on Friday night = 4 ft

Amount of  sausage links remaining = 8 - 4 = 4ft           (i)

Amount of  sausage links made on Saturday morning = 8 ft         (ii)

So,

Total amount of  sausage links = 8 + 4 = 12 ft   (from (i) and (ii) )

Amount of  sausage links used on Saturday night = 12 ft

Amount of sausage links remaining = 12 - 12 = 0 ft

Net change in the amount of sausage Sal had from Friday morning until after dinner service Saturday night = 8 - 0 = 8 ft

8 0
3 years ago
Heights of men have a bell-shaped distribution, with a mean of 176 cm and a standard deviation of 7 cm. Using the Empirical Rule
Vaselesa [24]

Answer:

a) 68% of the men fall between 169 cm and 183 cm of height.

b) 95% of the men will fall between 162 cm and 190 cm.

c) It is unusual for a man to be more than 197 cm tall.

Step-by-step explanation:

The 68-95-99.5 empirical rule can be used to solve this problem.

This values correspond to the percentage of data that falls within in a band around the mean with two, four and six standard deviations of width.

<em>a) What is the approximate percentage of men between 169 and 183 cm? </em>

To calculate this in an empirical way, we compare the values of this interval with the mean and the standard deviation and can be seen that this interval is one-standard deviation around the mean:

\mu-\sigma=176-7=169\\\mu+\sigma=176+7=183

Empirically, for bell-shaped distributions and approximately normal, it can be said that 68% of the men fall between 169 cm and 183 cm of height.

<em>b) Between which 2 heights would 95% of men fall?</em>

This corresponds to ±2 standard deviations off the mean.

\mu-2\sigma=176-2*7=162\\\\\mu+2\sigma=176+2*7=190

95% of the men will fall between 162 cm and 190 cm.

<em>c) Is it unusual for a man to be more than 197 cm tall?</em>

The number of standard deviations of distance from the mean is

n=(197-176)/7=3

The percentage that lies outside 3 sigmas is 0.5%, so only 0.25% is expected to be 197 cm.

It can be said that is unusual for a man to be more than 197 cm tall.

3 0
3 years ago
Jennifer taking a quiz and has answered 13 questions so far. If there are 25 questions on Jennifer test, how many questions does
Stels [109]

Answer: 12


Step-by-step explanation: To figure this out you have to subtract 25 by 13

                                                          25

                                                      -   13

                                                        = 12


7 0
3 years ago
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