The total length of rope, in feet, used to put up tents is 60 times the number of tents

Mathematics

2 answers:

harina [27]3 years ago

7 0

The total length of rope = r

is 60 times
the number of tents = t
r = 60t

solmaris [256]3 years ago

4 0

Answer:

Total length of the rope = 6x feet.

Step-by-step explanation:

Given : The total length of rope, in feet, used to put up tents is 60 times the number of tents

To find : Total length of the rope.

Solution: We have given

Let the number = x

Tenth of the number = $\frac{x}{10}$ .

According to question :

60 times the number of the tenths.

60 * $\frac{x}{10}$ .

Total length of the rope = 60 * $\frac{x}{10}$ .

Total length = 6 x .

Therefore, Total length of the rope = 6x feet .

You might be interested in

A ball is thrown from an initial height of 1 meter with an initial upward velocity of 15m/s. The ball's height h (in meters) aft

lakkis [162]

$\bf \stackrel{\textit{ball's height}~\hfill }{\stackrel{\downarrow }{h}=1+15t-5t^2}\implies \stackrel{\textit{ball's height}~\hfill }{\stackrel{\downarrow }{6}=1+15t-5t^2}\implies 0=-5+15t-5t^2 \\\\\\ ~~~~~~~~~~~~\textit{using the quadratic formula} \\\\ \stackrel{\stackrel{a}{\downarrow }}{5}t^2\stackrel{\stackrel{b}{\downarrow }}{-15}t\stackrel{\stackrel{c}{\downarrow }}{+5}=0 \qquad \qquad t= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a}$

$\bf t=\cfrac{-(-15)\pm\sqrt{(-15)^2-4(5)(5)}}{2(5)}\implies t=\cfrac{15\pm\sqrt{225-100}}{10} \\\\\\ t=\cfrac{15\pm\sqrt{125}}{10}\implies t=\cfrac{15\pm\sqrt{5^2 \cdot 5}}{10}\implies t=\cfrac{\stackrel{3}{~~\begin{matrix} 15 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}\pm ~~\begin{matrix} 5 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~\sqrt{5}}{\underset{2}{~~\begin{matrix} 10 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}$