Cost of aluminum required to make a ball of radius 7.5 inches is $ 161.71
<h3><u>Solution:</u></h3>
Given that
Goran's company makes solid balls out of scrap metal for various industrial uses.
For one project, he must make aluminum balls that have a radius of 7.5 inches.
Cost of aluminum = $0.12 per cubic inches
Need to determine cost of aluminum to make one ball.
Lets first calculate the volume of one ball
As shape of the ball is sphere
, we can use volume of sphere formula

Where "r" is the raius of ball
Given that radius of required ball = 7.5 inches


So quantity of aluminum required is same as volume of ball = 1347.5833 cubic inches
Cost of aluminum for 1 cubic inch = $0.12
<em><u>So cost of aluminum required to make a ball of aluminium of 1347.5833 cubic inches is given as:</u></em>

Answer:
n = 4
Step-by-step explanation:
4(2n + 3) = 44
Expand the brackets.
4(2n) + 4(3) = 44
8n + 12 = 44
Subtract 12 on both sides.
8n + 12 - 12 = 44 - 12
8n = 32
Divide both sides by 8.
(8n)/8 = 32/8
n = 4
Answer:
30,000 - 20% =24,000 year 1
24,000 - 20% =18,000 year 2
18,000 - 20% =12000 year 3
12,000 is your answer B)
Step-by-step explanation:
Answer:
x = 3
y = 2
Step-by-step explanation:
Given
y = -2x + 8
y = x - 1
Substitute x - 1 for y in the first equation
We have
y = -2x + 8
x - 1 = -2x + 8
Add 1 to both sides to eliminate 1 on the left side
x - 1 + 1 = -2x + 8 + 1
x = -2x + 9
Add 2x to both sides to eliminate 2x on the right side
x + 2x = -2x + 2x + 9
3x = 9
Divide both sides by 3 to isolate x
3x/3 = 9/3
x = 3
Now substitute 3 for x in either equations to get y
Using the second equation, we have
y = x - 1
y = 3 - 1
y = 2
x = 3 and
y = 2