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Alisiya [41]
3 years ago
8

PLEASEEEEEE HELPPPPPPPP

Mathematics
1 answer:
Natali5045456 [20]3 years ago
8 0
The formula for the sum of n terms in an arithmetic progression is:
S = n/2 * (2a + (n-1)d)
Here, the common difference, d, is 8 and the first term, a, is 1. Substituting these into the formula, we get:

S = n/2 * (2*1 + 8(n - 1))
S = n + 4n² - 4n
S = 4n² - 3n
The answer is A.
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