A. 6x + 5 + 9xb. 20 + 6x + 4 + 10x c. 32+ 20xd. 13x + 6 - (2 - 3x)
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Check the picture below
if that red segment, GJ, is parallel to the AE base segment of the triangle, then, the segment GJ is the midsegment of the triangle, and by the side-splitter theorem, those two triangles are similar.
if that red segment, GJ, is parallel to the AE base segment of the triangle, then, the segment GJ is the midsegment of the triangle, and by the side-splitter theorem, those two triangles are similar.
Step-by-step explanation:
Using the properties of logarithms, the left side of the equation becomes
while the right hand side becomes
so we end up with