Answer:
critical value = 5.29
Step-by-step explanation:
Given that they are divided into 4 groups and a sample of 5 test was selected
N = 5 * 4 = 20
k = 4
∝ = 0.01
Df for numerator ( SS group )= k - 1 = 3
Df for denominator ( SSE group ) = N - k = 20 - 4 = 16
DF ( degree of freedom )
Next we will use the F table to determine the critical value
Critical value =
= 5.29
Answer:
2. t=1.5(d)
Step-by-step explanation:
Part A- t=1.5(d)
Part B- 10.5
Step-by-step explanation:
EXAMPLE OF SURFACE AREA
1/2 × (30×4) × 39 + (30×30)
= 60 × 39 + 900
= 2340 + 900
= 3240
If you are looking for the equation of the line,
Use Point Slope Form

y-4 = 3(x-1)
y-4 = 3x-3
y = 3x + 1