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3 years ago

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The ratio of the heights of two similar cylinders is 1:3. If the volume of the smaller cylinder is 67 cubic cm, find the volume

of the larger cylinder

1 answer:

Andreyy893 years ago

8 0

The volume is 18.72

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Step-by-step explanation:

The Fundamental Theorem of Algebra states that the number of complex roots a polyomial has is equal to its highest exponent. This is a squared polynomial; second degree; quadratic. When it is factored, no matter what types of numbers you get as the solution, you will ALWAYS have 2 of them. When this quadratic is factored, we get that x = 3 and x = 3. That means that this is a quadratic that touches the x-axis at (3, 0). It doesn't go through, it only touches. We do have 2 roots, but since they're the same, we say we have a multiplicity 2 of that root. The closest you'll come to that in your choices is A. Apparently your text refers to multiplicity 2 as a double root.

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A rhombus has four 6-inch sides and two 120-degree angles. From one of the vertices of the obtuse angles, the two latitudes are

nikitadnepr [17]

Answer:

Area(A)=Area(C)= $9 in^{2}$

Area(B)= $13.2 in^{2}$

Step-by-step explanation:

We begin with finding the angles a and b that from the drawing attached you can see that a=b.

Now, the sum of the internal angles of a rhomboid is equal to 360 degrees, with that we have:

120+120+a+b=360

240+2a=360

2a=120

a=60=b

Next, in the image you can see that the lines coming from the angle at the top 120 degrees vertex, divide the opposite sides by half, thus making two triangles with one side of 6 in and another of 3 in.

We can say from the drawing as well:

Area(A)+Area(B)+Area(C)=Area(rhomboid)

But, we can also say that Area(A)=Area(C)

So, starting with Area(A)

Area(A)=Area(triangle)= $\frac{b*h}{2}$ = $\frac{6*3}{2}$ = $9 in^{2}$

We can then calculate the area B, a rhomboid, or better, take the Total area of the figure and subtract the area of the two triangles.

Area(B)=Area(rhomboid)-Area(A)-Area(C)

Area(rhomboid)=b*h where b=6in and h is the perpendicular distance from the base to the top.

$h=[tex]6*cos(30)=5.20in$ The 30 degrees come from: 120-30-60=30, since the latitudes split the 120 angle in two equal parts and one that is the half of the obtuse angle.

Area(rhomboid)=5.20*6= $31.2 in^{2}$

Area(B)=Area(rhomboid)-Area(A)-Area(C)= $31.2 in^{2}$ - $9 in^{2}$ - $9 in^{2}$ = $13.2 in^{2}$

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