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oksian1 [2.3K]
3 years ago
13

The ratio of the heights of two similar cylinders is 1:3. If the volume of the smaller cylinder is 67 cubic cm, find the volume

of the larger cylinder
Mathematics
1 answer:
Andreyy893 years ago
8 0
The volume is 18.72
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Consider the functions f(x) = 3x2, g(x)=1/3x , and h(x) = 3x. Which statements accurately compare the domain and range of the fu
Genrish500 [490]

Answer:

all of the functions have a unique range ⇒ answer 1

Step-by-step explanation:

* Lets revise how to find the domain and the range of the function

- The domain is all values of x that make the function defined

- The range is the set of all output values of a function

∵ f(x) = 3x²

- It is a quadratic function

- There is no values of x make this function undefined

∴ The domain of f(x) is all real numbers

- To find the range calculate the vertex of the function

∵ f(x) = ax² + bx + c

∵ f(x) = 3x²

∴ a = 3 , b = 0 , c = 0

∵ h = -b/2a

∴ h = 0/2(3) = 0/6 = 0

∵ k = f(h)

∴ k = f(0) = 3(0)² = 0

∴ The vertex of the cure is (0 , 0)

∵ k is the minimum value of the parabola

∴ The range of f(x) is all real numbers greater than or equal

  to zero ⇒ (1)

∵ g(x) = 1/3x

- It is a rational function

- to find the values of x which make the function undefined equate

 the denominator by 0

∵ 3x = 0 ⇒ divide both sides by 0

∴ x = 0

∴ The domain of g(x) is all real numbers except zero

∵ We can not put x = 0, then there is no value of g(x) at x = 0

∴ The range of the g(x) is all real number except zero ⇒ (2)

∵ h(x) = 3x

- It is a linear function

∵ There is no values of x make this function undefined

∴ The domain of h(x) is all real numbers

∴ The range of h(x) is all real numbers ⇒ (3)

* From (1) , (2) , (3) the answer is

 all of the functions have a unique range

# Look to the attached graph to more understand

The red graph is f(x)

The blue graph is g(x)

The green graph is h(x)

8 0
3 years ago
Read 2 more answers
What is the product?<br><br> (5r − 4)(r2 − 6r + 4)
maxonik [38]

Answer:

1r

Step-by-step explanation:

(5r-4)(2r-6r+4)

1(5r-4)+1(2r-6r+4)

5r-4+2r-6r+4

5r+2r-6=1r

1r-4+4

-4+4=0

1r

7 0
2 years ago
The rectangle below has an area of 70y^8+30y^6.The width of the rectangle is equal to the greatest common monomial factor of 70y
swat32

Answer:

Width 10y^6 units

Length 7y^2+3 units

Step-by-step explanation:

The rectangle has an area of 70y^8+30y^6.

The width of the rectangle is equal to the greatest common monomial factor of 70y^8 and 30y^6. Find this monomial factor:

70y^8=2\cdot 5\cdot 7\cdot y^8\\ \\30y^6=2\cdot 3\cdot 5\cdot y^6\\ \\GCF(70y^8,30y^6)=2\cdot 5\cdot y^6=10y^6

Hence, the width of the rectangle is 10y^6 units.

The area of the rectangle can be rewritten as

10y^6(7y^2+3).

The area of the rectangle is the product of its width by its length, then the length of the rectangle is 7y^2+3 units.

8 0
3 years ago
Jose left the white house and drove toward the recycling plant at an average of 40km/h. Rob left some time later driving in the
tiny-mole [99]
I would think it would be 200km before rob caught up with him?
6 0
3 years ago
Can somebody number the problem and work it out for me thanks and btw it’s solving system by graphics
adoni [48]

Answer:

Solutions are (3,1) and (4,2)

Step-by-step explanation:

Graph is shown in the attached sheet

Given are two systems of equations and we have to solve them using graph

For graphing let us first prepare table for x and y.

1) y=\frac{-2x}{3} +3:\\y=2x-5

I line                                                             II line

x     0   4.5    3                              x       0      2.5     3

y      3   0       1                              y       -5      0        1

The two lines intersect at (3,1)

Hence solution is (3,1)

--------------------------------------------

2) y=\frac{x}{2} \\-6x+3y=-18

I line                                                             II line

x     0    2    4                              x       0      6     4

y      0   1      2                             y       3      0     2

The two lines intersect at (4,2)

Hence solution is (4,2)

3 0
2 years ago
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