Question

PLEASE HELP! I don’t understand

Answer 1

Answer:

$\frac{\sqrt{2-\sqrt{3} } }{2}$

Step-by-step explanation:

$sin(\frac{u}{2} =\sqrt[+]{\frac{1-cosu}{2} } =\sqrt{\frac{1-cos30^0}{2} } \\=\sqrt{(\frac{1-\frac{\sqrt{3} }{2)} }{2} } \\=\sqrt{\frac{2-\sqrt{3} }{4} } \\=\sqrt{\frac{2-\sqrt{3} }{\sqrt{4} } } \\=\sqrt{\frac{2-\sqrt{3} }{2} }$

Answer 2

Answer:

sqrt(2-sqrt(3))/2

Step-by-step explanation:

sin(15)=sin(30/2)=sqrt(1-cos(x))/sqrt(2)=(1-sqrt(3)/2)/sqrt(2)

Again we don't like compound fractions so multiply top and bottom inside sqrt( ) by 2.

sin(15)=sqrt(2-sqrt(3))/sqrt(4)

simplify

sin(15)=sqrt(2-sqrt(3))/2