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3 years ago

What is the value of x?

Mathematics

1 answer:

Alisiya [41]3 years ago

3 0

Simplify the first numerator first
-2(x+1)
-2x-2

Then you can set up an equation using cross multiplication
5(-2x-2)= 3x

Simplify and solve
-10x-10=3x
-10=13x
-10/13=x

Final answer: x=-10/13

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I need help with my rsm hwrk pls help me

oksian1 [2.3K]

Answer: $A= 32(\pi-2)\ cm^2, \ \ \ P=8\pi\ cm$

Step-by-step explanation:

When we consider Area under arc AC is is representing a quarter as ADBC is a square, $\angle D=90^{\circ}$ .

Area of quadrant = $\dfrac{\pi r^2}{4}$

here r= 8 cm

Area under Arc AC= $\dfrac{\pi (8)^2}{4}=16\pi\ cm^2$

Area of white region ABC = Area of square ADBC - Area under Arc AC

$=8^2-16\pi\ \ [\text{Area of square} = sides^2]\\\\= 64-16\pi\ \ =16(4-\pi)\ cm^2$

Similarly , Area of white region ADC = $16(4-\pi)\ cm^2$

Area of shaded region = Area of square - Area of white region ABC - Area of white region ADC

$=64-(64-16\pi)-(64-16\pi)\\\\= 32\pi-64\ cm^2 \\\\= 32(\pi-2)\ cm^2$

Area of shaded region = $= 32(\pi-2)\ cm^2$

Length of arc AC = $\dfrac{Circumference}{4}=\dfrac{2\pi r}{4}$

$\dfrac{\pi (8)}{2}=4\pi cm$

Perimeter of shaded region = 2(AC) = $8\pi\ cm$

3 0

2 years ago

Sin theta = 24/25, cos theta > 0, Find cos(2theta)

Norma-Jean [14]

Well... you don't necessarily need to get the cosine value, in order to get the double angle

$\bf \textit{Double Angle Identities}
\\ \quad \\
sin(2\theta)=2sin(\theta)cos(\theta)
\\ \quad \\\\
cos(2\theta)=
\begin{cases}
cos^2(\theta)-sin^2(\theta)\\
\boxed{1-2sin^2(\theta)}\\
2cos^2(\theta)-1
\end{cases}
\\ \quad \\\\
tan(2\theta)=\cfrac{2tan(\theta)}{1-tan^2(\theta)}\\\\
-------------------------------\\\\
cos(2\theta )=1-2sin^2(\theta )\qquad \qquad sin(\theta )=\cfrac{24}{25}
\\\\\\
cos(2\theta )=1-2\left( \cfrac{24}{25} \right)^2\implies cos(2\theta )=-0.8432$

4 0

3 years ago

Read 2 more answers

I need help on this final problem

bulgar [2K]

Answer:

1/2 (1 - 10 d)

Hope This Helps & Good Luck ^^

8 0

3 years ago

You are standing 40 meters from the base of a tree that leans 8o away from you. The angle of elevation from you to the top of th

Y_Kistochka [10]

Answer:

the height of the tree is 15.49 m

Step-by-step explanation:

Step 1:

From the figure, we can determine ∠ATB by using the fact that the sum of all the angles in a triangle add up to 180°:

∠ ATB = 180° - 98° - 20°

∠ ATB = 62°

Step 2:

Therefore, using the law of sines, we can determine the height of the tree.

TB / sin(20°) = 40 / sin(62°)

TB = 40 × (sin(20°) / sin(62°))

TB = 15.49 m

Therefore, the height of the tree is 15.49 m

3 0

3 years ago

What is the equation for shifting the standard sine curve 2 units horizontally?

ratelena [41]

Just add the displacement value to variable. If this value is positive, the graph will move to the right, otherwise it will shift to left.

$f(\O)=sen(\O+x)$

Where: x=displacement value

If you notice any mistake in my English, please let me know, because I am not native.

3 0

3 years ago