Answer:
Step-by-step explanation:
When we consider Area under arc AC is is representing a quarter as ADBC is a square,
.
Area of quadrant = 
here r= 8 cm
Area under Arc AC= 
Area of white region ABC = Area of square ADBC - Area under Arc AC
![=8^2-16\pi\ \ [\text{Area of square} = sides^2]\\\\= 64-16\pi\ \ =16(4-\pi)\ cm^2](https://tex.z-dn.net/?f=%3D8%5E2-16%5Cpi%5C%20%5C%20%20%20%20%20%5B%5Ctext%7BArea%20of%20square%7D%20%3D%20sides%5E2%5D%5C%5C%5C%5C%3D%2064-16%5Cpi%5C%20%5C%20%20%3D16%284-%5Cpi%29%5C%20cm%5E2)
Similarly , Area of white region ADC = 
Area of shaded region = Area of square - Area of white region ABC - Area of white region ADC

Area of shaded region =
Length of arc AC = 

Perimeter of shaded region = 2(AC) = 
Well... you don't necessarily need to get the cosine value, in order to get the double angle
Answer:
1/2 (1 - 10 d)
Hope This Helps & Good Luck ^^
Answer:
the height of the tree is <em>15.49 m</em>
<em></em>
Step-by-step explanation:
Step 1:
From the figure, we can determine ∠ATB by using the fact that the sum of all the angles in a triangle add up to 180°:
∠ ATB = 180° - 98° - 20°
∠ ATB = 62°
Step 2:
Therefore, using the law of sines, we can determine the height of the tree.
TB / sin(20°) = 40 / sin(62°)
TB = 40 × (sin(20°) / sin(62°))
<em>TB = 15.49 m </em>
<em></em>
Therefore, the height of the tree is <em>15.49 m</em>
Just add the displacement value to variable. If this value is positive, the graph will move to the right, otherwise it will shift to left.
Where: x=displacement value
If you notice any mistake in my English, please let me know, because I am not native.