Answer:
Explanation:
The main thing for this equation is to follow the amount on each side. Count each element on each side. Then by looking at the numbers figure out what numerical digit would make them equal.
For example:
On the left we have
Cu=1 and Cl=2.
But on the right we have
Cu=1 and Cl=3.
In order for them to be the same, we must add a coefficient of 3 to CuCl2 (aq0 on the left and a coefficient of 3 to Cu(s) on the right.
Answer:
b) Linear molecule with two domains
Explanation:
The image represents a linear molecule with two domains.
The compound shown here is carbon dioxide in which a central carbon atom is surrounded by two oxygen atoms.
- This bond geometry is of the type AX₂
- In this linear molecule the bond angle is a perfect 180°
- The lone pairs are perfectly balanced out and will not cause distortion of the central carbon.
The value of ΔS° for reaction is - 22.2 J/K.mol
→ 
Calculation,
Given value of S°(J/K.mol) for
= 248.5
= 240.5
= 210.6
= 256.2
Formula used:
ΔS° (Reaction) = ∑S°(Product) - ∑S°(Reactant)
ΔS° = (256.2 + 210.6 ) - ( 248.5 + 240.5) = 466.8 - 489 = - 22.2 J/K.mol
The change in stander entropy of reaction is - 22.2 J/K.mol. The negative sign indicates the that entropy of reaction is decreases when reactant converted into product.
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Answer:
273 K
Explanation:
The temperature of a gas at STP is 273 K. This is equal to 0°C or 32°F.
Answer:
in a sold the particles are in a fixed position and can only vibrate on the spot but when it changes into a liquid the energy is used to weaken the bonds so there are weak forces of attraction between the particles, all particles are still touching each other but are now free to move around. Ina gas all the bonds are broken, the gas particles are free to move around anywhere and the more collisions there are, the more the pressure increases
