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FromTheMoon [43]
3 years ago
8

Which structural formula does not represent benzene? a hexagon with nothing drawn inside it a hexagon with a dotted circle drawn

inside it a hexagon with single and double dashes on alternating sides a hexagon with a circle drawn inside it?

Chemistry
2 answers:
boyakko [2]3 years ago
5 0
Answer:
            <span>A hexagon with nothing drawn inside it does not represent Benzene.

Explanation:

Below attached picture contains structures mentioned in given option.

Structure of Option-A is shown in Red Color.
</span>
Structure of Option-B is shown in Blue Color.

Structure of Option-C is shown in Green Color.

Structure of Option-D is shown in Orange Color.

Result:
          Except Option-A, all structures represent Benzene. Option-A in fact shows the structure of Cyclohexane.

kaheart [24]3 years ago
4 0

Answer:

a hexagon with nothing drawn inside

Explanation:

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What is the definition of outer layer? *
Nataly [62]

Answer:

1    being or located on the outside; external  

2    further from the middle or central part

Explanation:

4 0
3 years ago
For the reaction below, Kp = 1.59 at 100°C. If 1.0 g of SrCO3 is placed in an empty 5.00 L reactor and allowed to reach equilibr
Sergio [31]

Answer:

p_{CO_2}^{eq}=1.59atm

Explanation:

Hello, in this case, one could consider the undergoing chemical reaction as:

SrCO_3(s)\rightleftharpoons SrO(s)+CO_2(g)

Thus, since 1.0 g of strontium carbonate is placed, the equilibrium equation takes the following form, excluding the solid-stated species and considering just the carbon dioxide as it is gaseous:

Kp=p_{CO_2}^{eq}=1.59atm

Hence, since at the beginning there is no carbon dioxide, its pressure at equilibrium equals Kp:

Kp=p_{CO_2}^{eq}=1.59atm

Which was clearly defined above.

Best regards.

8 0
3 years ago
Neon is compressed from 100 kPa and 16°C to 500 kPa in an isothermal compressor. Determine the change in the specific volume and
Viktor [21]

Answer:

\Delta v=-0.952m^3/kg

\Delta h=0

Explanation:

In this case, since neon could be considered as an ideal gas, the specific volumes at the first and second state are respectively:

v_1=\frac{Rg*T_1}{p_1}=\frac{0.4119kJ/kg*K*289.15}{100kPa} =1.19m^3/kg\\

v_2=\frac{Rg*T_2}{p_2}=\frac{0.4119kJ/kg*K*289.15}{500kPa} =0.238m^3/kg\\

Thus, the change in the specific volume turns out:

\Delta v=v_2-v_1=0.238m^3/kg-1.19m^3/kg\\\Delta v=-0.952m^3/kg

Which value has sense for the compression.

In addition, the specific enthalpy change just depend on the temperature as it is an ideal gas, therefore, since the process es isothermic:

\Delta h=Cp\Delta T=0

Best regards.

3 0
4 years ago
A 24.00 mL sample of a solution of Pb(ClO3)2 was diluted with water to 52.00 mL. A 17.00 mL sample of the dilute solution was fo
klio [65]

Answer:

0.238 M

Explanation:

A 17.00 mL sample of the dilute solution was found to contain 0.220 M ClO₃⁻(aq). The concentration is an intensive property, so the concentration in the 52.00 mL is also 0.220 M ClO₃⁻(aq). We can find the initial concentration of ClO₃⁻ using the dilution rule.

C₁.V₁ = C₂.V₂

C₁ × 24.00 mL = 0.220 M × 52.00 mL

C₁ = 0.477 M

The concentration of Pb(ClO₃)₂ is:

\frac{0.477molClO_{3}^{-} }{L} \times \frac{1molPb(ClO_{3})_{2}}{2molClO_{3}^{-}} =0.238M

4 0
3 years ago
What does the number tell us about an atom that never changes
Leokris [45]
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6 0
4 years ago
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