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GalinKa [24]
3 years ago
11

Pleaseeee help me

Chemistry
1 answer:
scoundrel [369]3 years ago
6 0

Answer:

2Al (s) + 3CuCl2( aq) --> 2AlCl3 (aq) + 3Cu(s)

Explanation:

The main thing for this equation is to follow the amount on each side. Count each element on each side. Then by looking at the numbers figure out what numerical digit would make them equal.

For example:

On the left we have

Cu=1 and Cl=2.

But on the right we have

Cu=1 and Cl=3.

In order for them to be the same, we must add a coefficient of 3 to CuCl2 (aq0  on the left and a coefficient of 3 to Cu(s) on the right.

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What cellular component is responsible for energy production and metabolic processes?
AlekseyPX

The cellular component responsible for energy production and metabolic processes is mitochondria.

What is Mitochondria?

A double-membrane-bound organelle known as a mitochondrion is found in the majority of eukaryotic organisms. The majority of the cell's adenosine triphosphate, which is then used as a source of chemical energy throughout the cell, is produced by mitochondria using aerobic respiration.

Oxidative phosphorylation, which produces ATP using the energy released during the oxidation of the food we eat, is the traditional function of mitochondria. For the majority of biochemical and physiological processes, including growth, mobility, and equilibrium, ATP is used as the main energy source in turn.

To learn more about mitochondria click the given link

brainly.com/question/869305

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5 0
2 years ago
Calculate the theoretical carbonaceous and nitrogenous oxygen demand for:
serg [7]

Answer:

The correct answer is 129 mg and 232 mg.

Explanation:

Theoretical carbonaceous oxygen demand:

The reaction will be,  

C₂H₆O₂ + 5/2 O₂ ⇒ 2CO₂ + 3H₂O

Thus, for one mole of C₂H₆O₂ (ethylene glycol), 2.5 moles of O₂ is needed.  

The molecular mass of ethylene glycol is 62 grams per mole.  

The given mass of ethylene glycol is 100 mg or 0.1 grams

The moles of ethylene glycol will be,  

Moles = Weight/Molecular mass

= 0.1/62 = 1.613 × 10⁻³ mol

For 1.613 × 10⁻³ mol, the moles of O₂ will be,  

= 2.5×1.613×10⁻³

= 4.0.×10⁻³ × 32mol

= 0.129 grams or 129 mg.  

The theoretical nitrogenous oxygen demand is:  

The reaction will be,  

2NH₃-N + 9/2O₂ ⇒  4HNO2 + H₂O

Thus, for 2 moles of NH₃-N, 4.5 moles of O₂ is needed,  

Therefore, for 1 mol of NH₃-N, the oxygen required will be,  

= 4.5/2 = 2.25 mol

The given mass of NH₃-N is 100 mg, the moles of NH₃-N will be,  

Moles = 100×10⁻³/31 = 3.225 × 10⁻³ mol (The molecular mass of NH₃-N is 31 gram per mole)

The moles of O₂ is 2.25 × 3.225 × 10⁻³ = 7.258 × 10⁻³ mol.  

Now the mass of O2 will be,  

= 7.258 × 10⁻³ × 32

= 0.232 grams

= 232 mg

5 0
3 years ago
Suppose that CO2 in the atmosphere was held at a constant, natural level for a few thousand years. Then, CO2 was added to double
MissTica

Answer:

temperature before the increase in CO2 was a few degrees lower than temperature after the increase.

Explanation:

CO2 in the atmosphere has the property of trapping heat by absorbing it. So, with increase in the level of CO2 in the atmosphere the more heat will be absorbed by it and hence the temperature before the increase in CO2 was a few degrees lower than temperature after the increase.

Level of CO2 ∝ Temperature of the Earth

8 0
3 years ago
How many moles of gas would be present in a gas trapped within a 100.0 mL vessel at 25.0°C at a pressure of 2.50 atmospheres?
nika2105 [10]

Answer:

bjbchgchhvvjnkvgx

Explanation:

njvg id xgg

7 0
3 years ago
Glenn is heating water in a teakettle. The hotter water at the bottom of the kettle rises. The cooler water near the top sinks a
alexandr402 [8]
B. convection

Hope this helps!
5 0
3 years ago
Read 2 more answers
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