Area of full circle= πr^2
Area of a quadrant= πr^2/4
=(3.5)^2π/4
=12.25π/4
=3.06πcm squared.
Answer:
figured it out is 25
Step-by-step explanation:
hope this helps:)
Answer: Option <span>C. To get system B, the second equation in system A was replaced by the sum of that equation and the first equation multiplied by -3. The solution to system B will be the same as the solution to system A.
First equation of system A multiplied by -3:
(-3)(x+6y=5)
(-3)(x)+(-3)(6)=(-3)(5)
-3x-18=-15
Sum of the second equation of system A and the first equation multiplied by -3:
(-3x-18)+(3x-7y)=(-15)+(-35)
-3x-18+3x-7y=-15-35
-25y=-50
System B
x+6y=5
-25y=-50 </span>
<span>
-4c - 11 = 4c +21 add 4c to both sides
</span>
<span>
-4c - 11 + 4c = 4c + 21 + 4c simplify
- 11 = 8c + 21</span> <span> subtract 21 from both sides
- 11 - 21 = 8c + 21 - 21 </span><span>simplify
- 32 = 8c divide both sides by 8
c = - 4That's it
</span>
I hope you got
the idea
Answer:
Step-by-step explanation:
Sum of 3 angles of triangle= 180
147 + 4x + x = 180
147 +5x = 180
5x = 180 - 147
5x = 33
x = 33/5
x = 6•6 (Answer)
