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inna [77]
3 years ago
15

Untitled Question * 11 X (8 – 5) + 9 X (2 + 7) Your answer Untitled Question *

Mathematics
2 answers:
dimulka [17.4K]3 years ago
7 0
8-5 = 3
2+7 =9
11(3) + 9(9)
33+81 = 114
Your Answer: 114
ki77a [65]3 years ago
3 0
81+33= 114 pretty sure it’s 114
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-6x2 + 3k + 5.0 - 3.2-5x + 7k - 2
Harman [31]

Answer:

10k-5x-12.2

Step-by-step explanation:

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2 years ago
Dividing 3 digits by 2 digits lesson 3.6
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3 years ago
Dividing the polynomial P(x) by x-6 yields a quotient by Q(x) and a remainder of 5.
bazaltina [42]

Dividing the given polynomial by (x -6) gives quotient Q(x) and remainder 5 then for Q(-6) = 3 , P(-6) = -31and P(6) =5.

As given in the question,

P(x) be the given polynomial

Dividing P(x) by divisor (x-6) we get,

Quotient = Q(x)

Remainder = 5

Relation between polynomial, divisor, quotient and remainder is given by :

P(x) = Q(x)(x-6) + 5   __(1)

Given Q(-6) = 3

Put x =-6 we get,

P(-6) = Q(-6)(-6-6) +5

⇒ P(-6) = 3(-12) +5

⇒ P(-6) =-36 +5

⇒ P(-6) = -31

Now x =6 in (1),

P(6) = Q(6)(6-6) +5

⇒ P(6) = Q(6)(0) +5

⇒ P(6) = 5

Therefore, dividing the given polynomial by (x -6) gives quotient Q(x) and remainder 5 then for Q(-6) = 3 , P(-6) = -31and P(6) =5.

The complete question is:

Dividing the polynomial P(x) by x - 6 yields a quotient Q(x) and a remainder of 5. If Q(-6) = 3, find P(-6) and P(6).

Learn more about polynomial here

brainly.com/question/11536910

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11 months ago
Which equation represents the data shown in the table below
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2 years ago
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For the following problem, assume that all given angles are in simplest form, so that if A is in QIV you may assume that 270° &l
d1i1m1o1n [39]

Answer:

Step-by-step explanation:

Given that angle A is in IV quadrant

So A/2 would be in II quadrant.

sin A = -1/3

cos A = \sqrt{1-sin^2 A} =\frac{2\sqrt{2} }{3}

(cos A is positive since in IV quadrant)

Using this we can find cos A/2

cosA = 2cos^2 \frac{A}{2} -1\\Or cos \frac{A}{2} =-\sqrt{\frac{1+cosA}{2} } =-\sqrt{\frac{3+2\sqrt{2} }{6} }

3 0
2 years ago
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