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3 years ago

7

started with 12 ounces of water when should be getting her walk when she finished walking she had 2 1/4 ounce of water left how

much water did he drink

1 answer:

tekilochka [14]3 years ago

3 0

She drunk about

9 and 3/4 of her water

hope this helps :3

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PLEASE HELP ME ANSWER THESE TWO QUESTIONS!!!!!!!

Fittoniya [83]

1. x=50 2. x=4 hope this helps:)

8 0

2 years ago

A cheese processing company wants to estimate the mean cholesterol content of all one-ounce servings of a type of cheese. The es

Mrrafil [7]

Answer:

The minimum sample size required to construct a 95% confidence interval for the population mean is 65.

Step-by-step explanation:

We are given the following in the question:

Population standard deviation,

$\sigma = 3.10\text{ milligrams}$

We need to construct a 95% confidence interval such that the estimate is within 0.75 milligrams of the population mean.

Thus, the margin of error must me 0.75

Formula for margin of error:

$z_{critical}\times \dfrac{\sigma}{\sqrt{n}}$

$z_{critical}\text{ at}~\alpha_{0.05} = 1.96$

Putting values, we get,

$0.75 = 1.86\times \dfrac{3.10}{\sqrt{n}}\\\\\sqrt{n} = \dfrac{1.96\times 3.10}{0.75}\\\\\sqrt{n} = 8.101\\\Rightarrow n = 65.63\approx 65$

Thus, the minimum sample size required to construct a 95% confidence interval for the population mean is 65.

5 0

3 years ago

JAYDEN MADE SOME CANDLES THAT EACH WEIGHS 1/2 POUND. HE SHIP THEM IN A BOX THAT WEIGHT 6 POUNDS. THE TOTAL WEIGHT OF THE BOX FIL

Ahat [919]

Answer: 12

Step-by-step explanation:

6 0

3 years ago

It is known that the life of a particular auto transmission follows a normal distribution with mean 72,000 miles and standard de

scoray [572]

Answer:

a) $P(X$

$P(z$

b) $P(X>65000)=P(\frac{X-\mu}{\sigma}>\frac{65000-\mu}{\sigma})=P(Z>\frac{65000-72000}{12000})=P(z>-0.583)$

$P(z>-0.583)=1-P(Z$

c) $P(X>100000)=P(\frac{X-\mu}{\sigma}>\frac{100000-\mu}{\sigma})=P(Z>\frac{100000-72000}{12000})=P(z>2.33)$

$P(z>2.33)=1-P(Z$

Sicne this probability just represent 1% of the data we can consider this value as unusual.

d) $z=1.28$

And if we solve for a we got

$a=72000 +1.28*12000=87360$

So the value of height that separates the bottom 90% of data from the top 10% is 87360.

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Part a

Let X the random variable that represent the life of a particular auto transmission of a population, and for this case we know the distribution for X is given by:

$X \sim N(72000,12000)$

Where $\mu=72000$ and $\sigma=12000$

We are interested on this probability

$P(X$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(X$

And we can find this probability using excel or the normal standard table and we got:

$P(z$

Part b

$P(X>65000)$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(X>65000)=P(\frac{X-\mu}{\sigma}>\frac{65000-\mu}{\sigma})=P(Z>\frac{65000-72000}{12000})=P(z>-0.583)$

And we can find this probability using the complement rule and excel or the normal standard table and we got:

$P(z>-0.583)=1-P(Z$

Part c

$P(X>100000)$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(X>100000)=P(\frac{X-\mu}{\sigma}>\frac{100000-\mu}{\sigma})=P(Z>\frac{100000-72000}{12000})=P(z>2.33)$

And we can find this probability using the complement rule and excel or the normal standard table and we got:

$P(z>2.33)=1-P(Z$

Sicne this probability just represent 1% of the data we can consider this value as unusual.

Part d

For this part we want to find a value a, such that we satisfy this condition:

$P(X>a)=0.1$ (a)

$P(X$ (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.

As we can see on the figure attached the z value that satisfy the condition with 0.9 of the area on the left and 0.1 of the area on the right it's z=1.28. On this case P(Z<1.28)=0.9 and P(z>1.28)=0.1

If we use condition (b) from previous we have this:

$P(X$

$P(z$

But we know which value of z satisfy the previous equation so then we can do this:

$z=1.28$

And if we solve for a we got

$a=72000 +1.28*12000=87360$

So the value of height that separates the bottom 90% of data from the top 10% is 87360.

5 0

3 years ago

What is the equation of the following line? be sure to scroll down first to see all answer options

andreyandreev [35.5K]

Answer:

The equation for the following graph:

$y = -\frac{1}{5}x$

Step-by-step explanation:

- You first need to find the slope by using the <u>slope formula</u>:

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$

(where $(x_{1},y_{1})$ is the first point and $(x_{2}, y_{2})$ is the second point)

-Use the given points $(0,0)$ and $(10, -2)$ from the graph for the formula:

$m = \frac{-2 - 0}{10 - 0}$

Then, you solve:

$m = \frac{-2 - 0}{10 - 0}$

$m = -\frac{1}{5}$

After you have found the slope, use the slope $-\frac{1}{5}$ and the first point $(0,0)$ for the <u>point-slope formula:</u>

$y - y_{1} = m ( x - x_{1})$

<u>(</u>where $m$ is the slope and $(x_{1}, y_{1})$ is the first point)

$y - 0 = -\frac{1}{5} ( x - 0)$

Then, you solve:

$y - 0 = -\frac{1}{5} ( x - 0)$

$y - 0 = -\frac{1}{5}x - 0$

$y - 0 + 0 = -\frac{1}{5} - 0 + 0$

$y = -\frac{1}{5}x$

So, the equation for the following graph is $y = -\frac{1}{5}x$ .

7 0

2 years ago