I think this is it,please try and looking it up also for a better explanation
According to the identity if a+b+c=0
then a3+b3+c3=3abc
a3+b3+c3/abc=3
a2*a/bc*a+b2*b/ca*b+c2*c/ab*c=3
cancel a,b,c in all the fraction then you get
<span>a²/bc+b²/ca+c²/ab=3.
</span>hence proved
Answer:
zero and negative four
I hope that's what you meant I don't know
Step-by-step explanation:
f(x) = -(x - 2)
=-(2-2)
=0
f(x) = -(x - 2)
=-(6-2)
=-4
The charter bus will take 7 hours to get there, so they will get there at 1pm. Her parents would actually get there before the bus because it's only going to take 5 hours.
Answer: 13&7
Step-by-step explanation:
The sum of two numbers x&y is 20
Product of the 2numbers xy is 51
X+y=20......equation 1
XY=51.........equation 2
X=20-y.......equation 3
Substitute for x inequation 3 into equation 2
So we have;
(20-y)y=51
Open the bracket
20y-y^2=51
Collect like terms,so we have
Y2-20y+51=0
Factorise
Factors of 51 is 13&7
So -13-7=-20 &-13×-7=51
Substitute
Y2-13y-7y+51=0
Y(y-13)-7(y-13)=0
(Y-7)(y-13)=0
Y-7=0
Y=7 or
Y-13=0
Y=13
Y=13 or 7
Substitute for y in equation 1
X+y=20
X+7=20
X=20-7
X=13 or
X+13=20
X=20-13
X=7
Therefore, X &Y = 13 &7
