Ask question

Ask question

All categories

2 years ago

15

If u = 1 + i and v = 1 – i, what is u + v? A.2 B.0 C.-2i D.-2 E.2i

2 answers:

Gnoma [55]2 years ago

7 0

Answer:

2

Step-by-step explanation:

Remark

Treat that i as though it were any letter used as variable. The fact that it represents the square root of minus 1 is not an issue here. If you have 5x -5x the result is 0.

Same thing with this question

u + v = 1 + i + 1 - i = 2 The two "i"s cancel and the two "1"s add. The answer is 2

Scrat [10]2 years ago

3 0

Answer:

2

Step-by-step explanation:

u = 1+i

v = 1-i

add them together

1+i

1-i

------

2 +0

You might be interested in

Zak and Ryan earn $60 per week for delivering pizzas. Zak worked for x weeks and earned an additional total bonus of $25. Ryan w

Inessa05 [86]

Answer:

60x + 25 + 60y

Step-by-step explanation:

60 times x plus 60 times y plus 25

4 0

2 years ago

Read 2 more answers

Ok I rlly need help with this question it’s rlly hard for me there’s a picture to show —> helppp

Whitepunk [10]

Answer:

x=20; vertical angles theorem

Step-by-step explanation:

hi! we can use the vertical angles theorem for this. vertical angles are congruent to each other, meaning they are the same amount of degrees. so, we can set 2x+10 and 50 equal to each other.

2x+10=50

2x=40

x=20

x=20 because of the vertical angles theorem.

8 0

2 years ago

Unsure how to do this calculus, the book isn't explaining it well. Thanks

krok68 [10]

One way to capture the domain of integration is with the set

$D = \left\{(x,y) \mid 0 \le x \le 1 \text{ and } -x \le y \le 0\right\}$

Then we can write the double integral as the iterated integral

$\displaystyle \iint_D \cos(y+x) \, dA = \int_0^1 \int_{-x}^0 \cos(y+x) \, dy \, dx$

Compute the integral with respect to $y$ .

$\displaystyle \int_{-x}^0 \cos(y+x) \, dy = \sin(y+x)\bigg|_{y=-x}^{y=0} = \sin(0+x) - \sin(-x+x) = \sin(x)$

Compute the remaining integral.

$\displaystyle \int_0^1 \sin(x) \, dx = -\cos(x) \bigg|_{x=0}^{x=1} = -\cos(1) + \cos(0) = \boxed{1 - \cos(1)}$

We could also swap the order of integration variables by writing

$D = \left\{(x,y) \mid -1 \le y \le 0 \text{ and } -y \le x \le 1\right\}$

and

$\displaystyle \iint_D \cos(y+x) \, dA = \int_{-1}^0 \int_{-y}^1 \cos(y+x) \, dx\, dy$

and this would have led to the same result.

$\displaystyle \int_{-y}^1 \cos(y+x) \, dx = \sin(y+x)\bigg|_{x=-y}^{x=1} = \sin(y+1) - \sin(y-y) = \sin(y+1)$

$\displaystyle \int_{-1}^0 \sin(y+1) \, dy = -\cos(y+1)\bigg|_{y=-1}^{y=0} = -\cos(0+1) + \cos(-1+1) = 1 - \cos(1)$

7 0

10 months ago

hey can you help me w/ some math ?? i make $8.50 an hour. monday through sunday only wednesday’s off. how much will i have in 2

enot [183]

Answer:

$29252.1669

Approximately $29252.1

Step-by-step explanation:

For Monday, Tuesday and Sunday:

=> 8.50 x 5 x 3

=> 8.5 x 15

=> 127.5

I multiplied 8.5 and 5 because you work for 5 hours. Then multiplied them with 3 it is for 3 days.

For Friday, Saturday, Thursday:

=> 8.5 x 6 x 3

=> 8.5 x 18

=> 153

I multiplied 8.5 and 6 because you work for 6 hours. Then multiplied them with 3 because it is for 3 days.

In 1 week you get:

=> 153 + 127.5

=> 280.5

In 1 year there are 52.1429 weeks.

So, you get:

=> 52.1429 x 280.5

=> 14626.08345

For 2 years, you get:

=> 14626.08345x 2

=> 29252.1669

=> Approximately $29252.1

8 0

3 years ago

Solving the math function

Sunny_sXe [5.5K]

Answer: the answer is C

Step-by-step explanation: trust me took the final yesterday ‍♀️

3 0

1 year ago

Read 2 more answers