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3 years ago

Is 0/12 a rational or irrational number

Mathematics

1 answer:

kondor19780726 [428]3 years ago

6 0

I feel like it would be rational because 0/12 = 0, and 0 is a rational number.

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The owner of a new restaurant is designing a floor plan, and he is decided between two different seating arrangements

choli [55]

Answer:

idek

Step-by-step explanation:

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2 years ago

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A number of fiction books at a library was 3/4 of the total number of books. After 592 fiction books were donated to the library

Zielflug [23.3K]

There approximately 7133 books in the library;

Data;

Let the number of total books = x
Number of fictional books = 3/4x

<h3>Word Problem</h3>

To solve this problem, we simply need to use an equation to explain the word problem into mathematical statements.

Let the total number of books be represented by x

The number of fictional books = 3/4x

After 592 fictional books were donated;

$\frac{3x}{4} + 592 = \frac{5}{6}x$

Let collect like terms and solve

$\frac{3x}{4} +592 = \frac{5}{6} x\\\frac{5}{6}x - \frac{3x}{4} = 592\\ 0.083x=592\\x = 592/0.083\\x = 7132.53$

There approximately 7133 books in the library;

Learn more on word problems here;

brainly.com/question/13818690

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1 year ago

Math Help!!! How many x-intercepts does the graph of the function have?

dalvyx [7]

It can have however many x intercepts it wants,

<span>BUT, to be a function it must pass the vertical line test. </span>
<span>this means you have to look at the graph and see if a vertical line drawn anywhere hits the graph more than once. </span>
<span>if it hits it more than once, it is NOT a function.
</span>
An example is a polynomial function to the infinite degree. That is
f(x) = lim (n --> infinity) [ x^n]
but only 1 y intercept (vertical line test remember)

6 0

2 years ago

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7 cards are drawn from a standard deck of 52 playing cards. How many different 7-card hands are possible if the drawing is done

Vladimir [108]

Answer:

The number of different 7 card hands possibility is 133784560

Step-by-step explanation:

The computation of the number of different 7 card hands possibility is shown below:

Here we use the combination as the orders of choosing it is not significant

So,

The number of the different hands possible would be

= $^{52}C_7$

= 52! ÷ (7! × (52 - 7)!)

= 133784560

Hence, the number of different 7 card hands possibility is 133784560

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2 years ago

Solve and graph the following: -6 -8x >-5<br><br>

OverLord2011 [107]

Answer:

-1/8 > x

Step-by-step explanation:

Rewrite the equation to -1 > 8x, so -1/8 > x

Dot -1/8 on the number line, and everything on the left of that point( if right is positive ) is x .

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2 years ago

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