approvals necessary to bypass the policy
To be honest bro, i really don't know the answer
Answer:
(a) The algorithm is as follows:
count = 0
for i = 1 to n:
if x = xi:
count++
print(count)
(b) n comparisons
Explanation:
Solving (a):
Assume the integer to locate is x and the elements of the list are: 
Such that: 
The algorithm is as follows:
<em>count = 0</em>
<em>for i = 1 to n:</em>
<em> if x = xi:</em>
<em> count++</em>
<em>print(count)</em>
<em />
The above iterates through the count of the list (i.e. n) and makes comparison with each element of the list (i.e. element 1 to element n).
When a match is found, the count variable is incremented by 1 and printed at the end of the loop
Furthermore:
If there are 3 elements in the list, the algorithm makes 3 comparisons.
It makes 10 comparisons if there are 10 elements in the list.
<em>So: it makes n elements if there are n elements in the list</em>
The correct answer is A : Business Process
Answer:
#define LSH_RL_BUFSIZE 1024
char *lsh_read_line(void)
{
int bufsize = LSH_RL_BUFSIZE;
int position = 0;
char buffer = malloc(sizeof(char) bufsize);
int c;
if (!buffer) {
fprintf(stderr, "lsh: allocation error\n");
exit(EXIT_FAILURE);
}
while (1) {
// Read a character
c = getchar();
// If we hit EOF, replace it with a null character and return.
if (c == EOF || c == '\n') {
buffer[position] = '\0';
return buffer;
} else {
buffer[position] = c;
}
position++;
// If we have exceeded the buffer, reallocate.
if (position >= bufsize) {
bufsize += LSH_RL_BUFSIZE;
buffer = realloc(buffer, bufsize);
if (!buffer) {
fprintf(stderr, "lsh: allocation error\n");
exit(EXIT_FAILURE);
}
}
}
}
Explanation: