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podryga [215]
3 years ago
13

Mary had four friends over to study for a test. Before her friends arrived, she baked four pies to share equally among herself a

nd her friends. How much pie is each person going to get? (Please explain how you got the answer)
Mathematics
1 answer:
Yanka [14]3 years ago
7 0

Answer:

4/5 of a pie

Step-by-step explanation:

Since she is having 4 friends over there will be a total of 5 people. So then you would do 4 divided by 5 since you are dividing 4 pies to 5 people and you get 0.80, or 4/5

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While working at the drugstore, Grace earns $9.83 per hours. How many hours will it take grace to earn $49.15?
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5

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What is the slop of the line?<br><br><br> slope = 1/3<br>slope = -3 <br>slope = 3​
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3 years ago
Add.<br><br> Express your answer in simplest form. <br><br> 5 tenths + 3 tenths = ?
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 0.5

+0.3
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7 0
3 years ago
Read 2 more answers
Mr. and Mrs. Romero are expecting triplets. Suppose the chance of each child being a boy is 50% and of being a girl is 50%. Find
Papessa [141]

Answer:

1) \text{P(at least one boy and one girl)}=\frac{3}{4}

2) \text{P(at least one boy and one girl)}=\frac{3}{8}

3) \text{P(at least two girls)}=\frac{1}{2}

Step-by-step explanation:

Given : Mr. and Mrs. Romero are expecting triplets. Suppose the chance of each child being a boy is 50% and of being a girl is 50%.

To  Find : The probability of each event.  

1) P(at least one boy and one girl)

2) P(two boys and one girl)

3) P(at least two girls)        

Solution :

Let's represent a boy with B and a girl with G

Mr. and Mrs. Romero are expecting triplets.

The possibility of having triplet is

BBB, BBG, BGB, BGG, GBB, GBG, GGB, GGG

Total outcome = 8

\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total number of outcome}}

1) P(at least one boy and one girl)

Favorable outcome =  BBG, BGB, BGG, GBB, GBG, GGB=6

\text{P(at least one boy and one girl)}=\frac{6}{8}

\text{P(at least one boy and one girl)}=\frac{3}{4}

2) P(at least one boy and one girl)

Favorable outcome =  BBG, BGB, GBB=3

\text{P(at least one boy and one girl)}=\frac{3}{8}

3) P(at least two girls)

Favorable outcome = BGG, GBG, GGB, GGG=4

\text{P(at least two girls)}=\frac{4}{8}

\text{P(at least two girls)}=\frac{1}{2}

4 0
3 years ago
Read 2 more answers
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