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OleMash [197]
3 years ago
7

One third of the square root of which number is 0.001

Mathematics
1 answer:
vladimir1956 [14]3 years ago
7 0
0.001*3=0.003
0.003^2=0.000009
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85.87 J or heat energy is added to a 34.8 g mass of substance the temperature rises from 21.76°C
Andru [333]

Answer:

The required specific heat is 196.94 joule per kg per °C  

Step-by-step explanation:

Given as :

The heat generated = Q = 85.87 J

Mass of substance  (m)= 34.8 gram = 0.0348 kg

Change in temperature = T2 - T1 = 34.29°C - 21.76°C = 12.53°C

Let the specific heat = S

Now we know that

Heat = Mass × specific heat × change in temperature

Or, Q = msΔt

Or, 85.87 = (0.0348 kg ) × S × 12.53°C

Or , 85.87 = 0.4360 × S

Or, S = \frac{85.87}{0.4360}

∴ S = 196.94 joule per kg per °C

Hence the required specific heat is 196.94 joule per kg per °C   Answer

7 0
3 years ago
Gary used candle molds, as shown, to make candles that were perfect cylinders and spheres:
Nimfa-mama [501]

Answer:

A

Step-by-step explanation:

Find the volume of both shapes.

Cylinder - V = πr²h = π·2²·4 = 50.26548

Sphere - V = 4/3πr³ = 4/3π·2³ = 33.51032

Find the difference between the two.

50.26548 - 33.51032 = 16.75516, or 16.75

-hope it helps

6 0
2 years ago
Somebody please help me with this geometry work
dimulka [17.4K]

Answer:

m∠EGF = 65°  and m∠CGF = 115°

Step-by-step explanation:

Given;

∠EFG = 50°

EF = FG

Solution,

In ΔEFG m∠EFG = 50° and EF = FG.

Since triangle is an isosceles triangle hence their base angles are always equal.

∴m\angle FEG = m\angle EGF

Let the measure of ∠EGF  be x.

∴ m\angle FEG = m\angle EGF = x

Now by angle Sum property which states "The sum of all the angles of a triangle is 180°."

m∠EFG + m∠FEG + ∠EGF = 180

50\°+x+x=180\°\\50\°+2x=180\°\\2x= 180\°-50\°\\2x=130\°\\x=\frac{130}{2}= 65\°

Hence

m∠EGF = 65°  

Also 'The sum of angles that are formed on a straight line is equal to 180°."

m∠EGF + m∠CGF = 180°

65° + m∠CGF = 180°

m∠CGF = 180° - 65° = 115°

Hence m∠EGF = 65°  m∠CGF = 115°

8 0
3 years ago
Suppose that you want to design a cylinder with the same volume as a given cylinder but you want to use a diff radius and height
Anton [14]

Answer:

Yes, r and h can be changed to produce same volume by;

Increasing "r" and decreasing "h" or by decreasing "r" and increasing "h".

Step-by-step explanation:

What the question is simply asking is if we can get same volume of a particular cylinder if we change the radius and height.

Now, volume of a cylinder is;

V = πr²h

Now, for the volume to remain the same, if we increase "r", it means we have to decrease "h", likewise, if we decrease "r", we now have to increase "h".

5 0
3 years ago
Write 46,056 in expanded form
kakasveta [241]
Fourty six thousand and fifty six. In expanded form it'll look like this:

40,000
6,000
0
50
6
3 0
3 years ago
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