Step-by-step explanation:
Determine the data range of the data set.
Decide the width of the class intervals.
Divide the range by the chosen width of the class interval to determine the number of intervals.
Answer:
1.00434
Step-by-step explanation:
Given the following :
Given a normal distribution ;
Mean (m) = 1.0 liter
Standard deviation (σ) = 0.01 liter
Sample size (n) = 25
For 97% sample means (sm) = 0.97
Z = (m - sm) / s
Zcrit = 1 - (100% - 97%)/2
Zcrit = 1 - (0.03/2)
Zcrit = 1 - 0.015 = 0.985
The z score which corresponds to 0.985 = 2.17
Upper limit : m + z*(σ/√n)
Upper limit : 1.0 + 2.17*(0.01/√25)
Upper limit : 1. 0 + 2.17*(0.01/5)
= 1.0 + 2.17*0.002
= 1.0 + 0.00434
= 1.00434
Answer:
The computation of the given question is shown below:-
Total Contributions = Monthly contribution + Amount invested in Ferdinand’s 401(k)
= $250 + $125
= $375
1. Future Value = PMT [((1 + r)n - 1) ÷ r
Future value = 375 × ((1 + 0.03 ÷ 12) × 12 × 40 - 1) ÷ (0.03 ÷ 12)
= $347,272
2. Ferdinand deposit = Given Amount × Total number of months in a year × Number of years
= $250 × 12 Months × 40 Years
= $120,000
3. The Amount put in by the employer = 50% of $250 ×Total number of months in a year × Number of years
= $125 × 12 Months × 40 Years
= $60,000
4. Interest = Future value - Ferdinand deposit - The Amount put in by the employer
= $347,272 - $120,000 - $60,000
= $167,272
Step-by-step explanation:
