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Ugo [173]
3 years ago
13

If the sin 30 degrees is 1/2 then the cos ____=____.

Mathematics
2 answers:
goldenfox [79]3 years ago
7 0
  Try A) 60 degrees; 1/2. Your answer was incorrect because cos(60 degrees) is 1/2, cos(30 degrees) is square root 3 /2 not 1 or square root 2 /2
Likurg_2 [28]3 years ago
7 0
 the answer is 4 becasue you just see how many pairs can each marble get
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A (0,5)<br> B (3, 11)<br> What’s the equation
slava [35]
Y=2x+5
goes up by 2, which is the gradient and 5 is the y intercept
6 0
1 year ago
The admission fee at a water park is $12.50 for children and $25.00 for adults On a certain day 352 people entered the park and
N76 [4]

Answer:

Children = 137

Adults = 215

Step-by-step explanation:

The admission fee at a water park is $12.50 for children

and $25.00 for adults.

On a certain day, 352 people entered the park and the admission fees collected totalled $6,687.50

Let the number of children admitted be x ,

and the number of adults admitted be y.

This forms a simultaneous equation:

x + y = 352 ... (i)

$12.50x + $25.00y = $6,687.50 ... (ii)

Multiplyng (i) by 12.50 and (ii) by 1 we get;

12.5x + 12.5y = 4400 ... (i)

12.5x + 25y = 6,687.5 ... (ii)

Subtracting (ii) - (i) we get;

12.5y = 2687.5

y = 215

So the number of adults admitted = 215

And the number of children admitted = 352 - 215 = 137

6 0
3 years ago
URGENT HELP ME PLEASE
Trava [24]

Answer:

(a)\log_3(\dfrac{81}{3})=3

(b)\log_5(\dfrac{625}{25})=2

(c)\log_2(\dfrac{64}{8})=3

(d)\log_4(\dfrac{64}{16})=1

(e)\log_6(36^4)=8

(f)\log(100^3)=6

Step-by-step explanation:

Let as consider the given equations are \log_3(\dfrac{81}{3})=?,\log_5(\dfrac{625}{25})=?,\log_2(\dfrac{64}{8})=?,\log_4(\dfrac{64}{16})=?,\log_6(36^4)=?,\log(100^3)=?.

(a)

\log_3(\dfrac{81}{3})=\log_3(27)

\log_3(\dfrac{81}{3})=\log_3(3^3)

\log_3(\dfrac{81}{3})=3        [\because \log_aa^x=x]

(b)

\log_5(\dfrac{625}{25})=\log_5(25)

\log_5(\dfrac{625}{25})=\log_5(5^2)

\log_5(\dfrac{625}{25})=2        [\because \log_aa^x=x]

(c)

\log_2(\dfrac{64}{8})=\log_2(8)

\log_2(\dfrac{64}{8})=\log_2(2^3)

\log_2(\dfrac{64}{8})=3        [\because \log_aa^x=x]

(d)

\log_4(\dfrac{64}{16})=\log_4(4)

\log_4(\dfrac{64}{16})=1        [\because \log_aa^x=x]

(e)

\log_6(36^4)=\log_6((6^2)^4)

\log_6(36^4)=\log_6(6^8)

\log_6(36^4)=8            [\because \log_aa^x=x]

(f)

\log(100^3)=\log((10^2)^3)

\log(100^3)=\log(10^6)

\log(100^3)=6            [\because \log10^x=x]

5 0
3 years ago
A highway passes under a road. The clearance height is 7.75 feet write and graph an inequality that represents the height of a v
san4es73 [151]
0 is less than or equal X is less than 7.75
8 0
3 years ago
What is −10−f=−6f+10
sammy [17]
-10-f=-6f+10
-f+6f=10+10
5f=20
F=4
4 0
3 years ago
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