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Naya [18.7K]
3 years ago
8

What is 15x-10x^3 I really need help or I’m gonna get detention

Mathematics
2 answers:
Anna71 [15]3 years ago
4 0

Answer:

I think that x=multiplication for you and if it´s like that the result is -15.000

Step-by-step explanation:

bixtya [17]3 years ago
3 0

Answer:

Step-by-step explanation:

15x-10x^3

= 15x - 10x³

= 5x(3 - 2x²)

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TV and YW are parallel lines.
Lemur [1.5K]

Answer: C, WXZ and WXU are adjacent angles.

Step-by-step explanation:

A is incorrect because TUX and VUS are vertical angles.

B is incorrect because YXZ and TUX have no relationship.

C is correct  because WXZ and WXU are supplementary angles, thus adjacent.

D is inccorect because VUX and TUS are vertical angles.

6 0
3 years ago
Q10. Assertion: 2.05 Kg = 20500 g.
jeyben [28]

Answer:

b. only reason is correct

2.05 kg=2.05 ×1000 g

=2050 g

so the Assertion is incorrect

5 0
3 years ago
The system of equations y=4x y-4=4 (x-1) has.
Alekssandra [29.7K]

Answer:

infinitely many solutions.

Step-by-step explanation:

y=4x

y-4=4 (x-1)

Lets substitute the first equation into the second equation.

4x -4 = 4(x-1)

Distribute

4x-4 = 4x-4

Subtract 4x from each side

4x-4x-4 =4x-4x-4

-4=-4

This is always true.  X can be anything.  We have infinite solutions

6 0
4 years ago
Read 2 more answers
the sum of Julio's and Charles's age is 44 years. seven year from now, Julio will be twice Charles's age. how old is each one no
Wewaii [24]
J + C = 44

J + 7 = 2C

I hope this helps. :)
3 0
4 years ago
Read 2 more answers
exam p A drawer contains four pairs of socks, with each pair a different color. One sock at a time is randomly drawn from the dr
Marta_Voda [28]

Answer:

The probability that the maximum number of draws is required is 0.2286

Step-by-step explanation:

The probability that the maximum number of draws happens when you pick <em>different colors in the first four pick</em>.

Assume you picked one sock in the first draw. Its probability is 1, since you can draw any sock.

In the second draw, 7 socks left and you can draw all but the one which is the pair of the first draw. Then the probability is \frac{6}{7}

In the third draw, 6 socks left and you can draw one of the two pair colors which are not drawn yet. Its probability is \frac{4}{6}

In the forth draw, 5 socks left and only one pair color, which is not drawn. The probability of drawing one of this pair is \frac{2}{5}

In the fifth draw, whatever you draw, you would have one matching pair.

The probability combined is 1×\frac{6}{7} ×\frac{4}{6}× \frac{2}{5} ≈ 0.2286

5 0
3 years ago
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