Use 5 as the lowest common factor and you gt 3/20
Answer:
1. 1.96 g/L
2. 1 g/cm³
Step-by-step explanation:
Density is found by dividing mass by volume: d = m/v.
1.
We know that the mass is 0.196 grams, while the volume is 100 mL.
Converting the volume to liters, we get:
100 mL = 0.1 L
Then, applying our density formula:
d = m/v
d = 0.196 g / 0.1 L = 1.96 g/L
2.
Here, we know that the mass is 27 grams. However, we don't know the volume, which we need to find.
The block of wood is 3 cm on all sides, which means it's a cube. The volume of a cube is denoted by V = s³, where s is the side length. Here, s = 3, so V = s³ = 3³ = 27 cm³.
Applying our density formula gives:
d = m/v
d = 27 g / 27 cm³ = 1 g/cm³
<em>~ an aesthetics lover</em>
Answer:
(a). 72.9%.
(b). 13.6 hr.
Step-by-step explanation:
So, we are given the following data or parameters or information which is going to assist us in solving this question/problem;
=> "A welder produces 7 welded assemblies during the first day on a new job, and the seventh assembly takes 45 minutes (unit time). "
=> The worker produces 10 welded assemblies on the second day, and the 10th assembly on the second day takes 30 minutes"
So, we will be making use of the Crawford learning curve model.
T(7) + 10 = T (17) = 30 min.
T(7) = T1(7)^b = 45.
T(17 ) = T1(17)^b = 30.
(T1) = 45/7^b = 30/17^b.
45/30 = 7^b/17^b = (7/17)^b.
1.5 = (0.41177)^b.
ln 1.5 = b ln 0.41177.
0.40547 = -0.8873 b.
b = - 0.45696.
=> 2^ -0.45696 = 0.7285.
= 72.9%.
(b). T1= 45/7^ - 045696 = 109.5 hr.
V(TT)(17) = 109.5 {(17.51^ - 0.45696 – 0.51^ - 0.45696) / (1 - 0.45696)} .
V(TT) (17) = 109.5 {(4.7317 - 0.6863) / 0.54304} .
= 815.7 min .
= 13.595 hr.
Answer:
1/25 k^2
Step-by-step explanation:
Answer:
45 degrees
Step-by-step explanation:
Ok I think it is 45 degrees try that if not super sorry
