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katovenus [111]
3 years ago
8

Standard deviation of 300, 785, 670, 187, 760, 724

Mathematics
1 answer:
White raven [17]3 years ago
7 0
STEP 1

Mean = \frac{300+785+670+187+760+724}{6} = \frac{3426}{6}=571

STEP 2

Subtract the mean from each data value then square the answer
300-571=-271 ⇒ (-271)^{2} =73441
785-571=214 ⇒ (214)^{2}=45796
670-571=99 ⇒ (99)^{2}=9801
187-571=-384 ⇒ (-384)^{2} =147456
760-571=189 ⇒ 189^{2}=35721
724-571=153 ⇒ 153^{2} =23409

STEP 3

Add the squared answers in STEP 2 then find the mean

\frac{73441+45796+9801+147456+35721+23409}{6}= \frac{335624}{6}=55937.3

STEP 4

Square root the answer in STEP 3
\sqrt{55937.3} =236.5

Standard deviation is 236.5
 
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2 years ago
Ann is adding water to a swimming pool at a constant rate. The table below shows the amount of water in the pool after different
N76 [4]

Answer:

(a)  As time increases, the amount of water in the pool increases.

     11 gallons per minute

(b)  65 gallons

Step-by-step explanation:

From inspection of the table, we can see that <u>as time increases, the amount of water in the pool increases</u>.

We are told that Ann adds water at a constant rate.  Therefore, this can be modeled as a linear function.  

The rate at which the water is increasing is the <em>rate of change</em> (which is also the <em>slope </em>of a linear function).

Choose 2 ordered pairs from the table:

\textsf{let}\:(x_1,y_1)=(8, 153)

\textsf{let}\:(x_2,y_2)=(12,197)

Input these into the slope formula:

\textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{197-153}{12-8}=\dfrac{44}{4}=11

Therefore, the rate at which the water in the pool is increasing is:

<u>11 gallons per minute</u>

To find the amount of water that was already in the pool when Ann started adding water, we need to create a linear equation using the found slope and one of the ordered pairs with the point-slope formula:

y-y_1=m(x-x_1)

\implies y-153=11(x-8)

\implies y-153=11x-88

\implies y=11x-88+153

\implies y=11x+65

When Ann had added no water, x = 0.  Therefore,

y=11(0)+65

y=65

So there was <u>65 gallons</u> of water in the pool before Ann starting adding water.

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As you can tell, when they share a common denominator (4), the numerators are the same as well (3).

~

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